What is the center of the circle x^2 + y^2 - 121 = 0? Simplify any fractions. (____,____)

Move Constant Other Side: x^2 + y^2 - 121 = 0 Move the constant to the other side. Add 121 on both sides. x^2 + y^2 - 121 + 121 = 0 + 121 x^2 + y^2 = 121Add Constant Both Sides: x^2 + y^2 = 121 Find the values of h and k compared to (x-h)^2 + (y-k)^2 = r^2. Standard form of a circle: (x-h)^2 + (y-k)^2 = r^2 Comparing the standard form and x^2 + y^2 = 121, we see that: h = 0 k = 0Find Values Compared: We found: h = 0 k = 0 What is the center of the circle x^2 + y^2 - 121 = 0? Substitute 0 for h and 0 for k in (h,k). Center of circle: (0,0)

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What is the center of the circle $x^2 + y^2 - 121 = 0$ ? $\newline$ Simplify any fractions. $\newline$ $(\_,\_)$

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Find properties of circles from equations in general form

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Q. What is the center of the circle

x^2 + y^2 - 121 = 0

\newline

Simplify any fractions.

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(\_,\_)

Move Constant Other Side: $x^2 + y^2 - 121 = 0$ Move the constant to the other side. Add $121$ on both sides. $x^2 + y^2 - 121 + 121 = 0 + 121$ $x^2 + y^2 = 121$
Add Constant Both Sides: $x^2 + y^2 = 121$ $\newline$ Find the values of $h$ and $k$ compared to $(x-h)^2 + (y-k)^2 = r^2$ . $\newline$ Standard form of a circle: $(x-h)^2 + (y-k)^2 = r^2$ $\newline$ Comparing the standard form and $x^2 + y^2 = 121$ , we see that: $\newline$ $h = 0$ $\newline$ $k = 0$
Find Values Compared: We found: $\newline$ $h = 0$ $\newline$ $k = 0$ $\newline$ What is the center of the circle $x^2 + y^2 - 121 = 0$ ? $\newline$ Substitute $0$ for $h$ and $0$ for $k$ in $(h,k)$ . $\newline$ Center of circle: $(0,0)$