Q. What is the center of the circle x2+y2−1=0?Simplify any fractions.(_,_)
Move Constant Other Side:x2+y2−1=0 Move the constant to the other side. Add 1 on both sides. x2+y2−1+1=0+1x2+y2=1
Standard Form Comparison:x2+y2=1Find the values of h and k compared to (x−h)2+(y−k)2=r2.Standard form of a circle: (x−h)2+(y−k)2=r2Comparing the standard form and x2+y2=1, we see that:h=0k=0
Center of Circle: We found:h=0k=0What is the center of the circle x2+y2−1=0?Substitute 0 for h and 0 for k in (h,k).Center of circle: (0,0)
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