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What is (f−g)(x)(f - g)(x)?\newlinef(x)=−x2f(x) = -x^2\newlineg(x)=2x+1g(x) = 2x + 1\newlineWrite your answer as a polynomial or a rational function in simplest form.\newline______

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Full solution

Q. What is (f−g)(x)(f - g)(x)?\newlinef(x)=−x2f(x) = -x^2\newlineg(x)=2x+1g(x) = 2x + 1\newlineWrite your answer as a polynomial or a rational function in simplest form.\newline______
  1. Identify Formula: Identify the formula for (f−g)(x)(f - g)(x). The correct formula is (f−g)(x)=f(x)−g(x)(f - g)(x) = f(x) - g(x).
  2. Substitute Values: We have f(x)=−x2f(x) = -x^2 and g(x)=2x+1g(x) = 2x + 1. Substitute these values into the formula to get (f−g)(x)=(−x2)−(2x+1)(f - g)(x) = (-x^2) - (2x + 1).
  3. Simplify Equation: Simplify the equation (f−g)(x)=(−x2)−(2x+1)(f - g)(x) = (-x^2) - (2x + 1) to find (f−g)(x)(f - g)(x).(f−g)(x)=−x2−2x−1(f - g)(x) = -x^2 - 2x - 1

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