Victor wants to learn to snowboard. He went to Snowy Ridge Mountain and rented a snowboard for 35$, then took 5 hours of group snowboarding lessons. Victor paid 175$ in all.Which equation can you use to find how much Snowy Ridge charges, x, for each hour of group snowboarding lessons?Choices:(A) 5x+35=175(B) 35(x+5)=175(C) 35x+5=175(D) 5(x+35)=175How much does Snowy Ridge charge for each hour of group snowboarding lessons?____ $
Q. Victor wants to learn to snowboard. He went to Snowy Ridge Mountain and rented a snowboard for 35$, then took 5 hours of group snowboarding lessons. Victor paid 175$ in all.Which equation can you use to find how much Snowy Ridge charges, x, for each hour of group snowboarding lessons?Choices:(A) 5x+35=175(B) 35(x+5)=175(C) 35x+5=175(D) 5(x+35)=175How much does Snowy Ridge charge for each hour of group snowboarding lessons?____ $
Understand the problem: Understand the problem.Victor rented a snowboard for a flat fee of $35 and took 5 hours of lessons, paying a total of $175. We need to find the cost per hour for the lessons, represented by x.
Set up the equation: Set up the equation.The total cost is the sum of the flat fee and the cost of the lessons. The cost of the lessons is the number of hours times the cost per hour. So the equation is:Cost of snowboard rental + (Cost per hour of lessons × Number of hours) = Total cost35+(x×5)=175
Identify the correct equation: Identify the correct equation from the choices.Looking at the choices given, we need to find the one that matches the equation we set up in Step 2.(A) 5x+35=175 is the correct equation because it represents the cost of the snowboard rental plus the cost of 5 hours of lessons.
Solve the equation for x: Solve the equation for x.5x+35=175Subtract 35 from both sides to isolate the term with x.5x=175−355x=140Now, divide both sides by 5 to solve for x.x=5140x=28
Verify the solution: Verify the solution.Plug the value of x back into the equation to ensure it satisfies the total cost.5(28)+35=175140+35=175175=175The solution is correct.
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