Vector vec(AB) has an initial point (7,-4), an x component of -10 , and a y component of -5 . Find the coordinates of the terminal point, B. B=(◻,◻)

Add components to initial point: To find the terminal point B of the vector vec(AB), we need to add the vector's components to the coordinates of the initial point A.Find x coordinate of point B: The x component of vec(AB) is -10. To find the x coordinate of point B, we add this component to the x coordinate of point A. So, x coordinate of B = x coordinate of A + x component of vec(AB) = 7 + (-10) = -3.Find y coordinate of point B: The y component of vec(AB) is -5. To find the y coordinate of point B, we add this component to the y coordinate of A. So, y coordinate of B = y coordinate of A + y component of vec(AB) = -4 + (-5) = -9.Coordinates of terminal point B: The coordinates of the terminal point B are therefore (-3, -9).

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Vector
vec(AB) has an initial point
(7,-4), an
x component of -10 , and a
y component of -5 .
Find the coordinates of the terminal point,
B.

B=(◻,◻)

Vector $\overrightarrow{A B}$ has an initial point $(7,-4)$ , an $x$ component of $-10$ , and a $y$ component of $-5$ . $\newline$ Find the coordinates of the terminal point, $B$ . $\newline$ $B=(\square, \square)$

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Algebra 2

Write equations of cosine functions using properties

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Q. Vector

\overrightarrow{A B}

has an initial point

(7,-4)

, an

x

component of

-10

, and a

y

component of

-5

\newline

Find the coordinates of the terminal point,

B

\newline

B=(\square, \square)

Add components to initial point: To find the terminal point $B$ of the vector $\vec{AB}$ , we need to add the vector's components to the coordinates of the initial point $A$ .
Find x coordinate of point B: The x component of $\vec{AB}$ is $-10$ . To find the x coordinate of point B, we add this component to the x coordinate of point A. $\newline$ So, x coordinate of B = x coordinate of A + x component of $\vec{AB}$ = $7 + (-10) = -3$ .
Find y coordinate of point B: The y component of $\vec{AB}$ is $-5$ . To find the y coordinate of point B, we add this component to the y coordinate of A. $\newline$ So, y coordinate of B = y coordinate of A + y component of $\vec{AB}$ = $-4 + (-5) = -9$ .
Coordinates of terminal point B: The coordinates of the terminal point B are therefore $(-3, -9)$ .