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For a given input value a, the function f outputs a value b to satisfy the following equation. -3a+6b=a+4b Write a formula for f(a) in terms of a. f(a)=◻

For a given input value aa, the function ff outputs a value bb to satisfy the following equation.\newline−3a+6b=a+4b-3a+6b=a+4b\newlineWrite a formula for f(a)f(a) in terms of aa.\newlinef(a)=□f(a)=\square

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Q. For a given input value aa, the function ff outputs a value bb to satisfy the following equation.\newline−3a+6b=a+4b-3a+6b=a+4b\newlineWrite a formula for f(a)f(a) in terms of aa.\newlinef(a)=□f(a)=\square
  1. Isolate bb on one side: To solve for bb in terms of aa, we need to isolate bb on one side of the equation. Let's start by moving all terms involving bb to one side and all terms involving aa to the other side.\newline−3a+6b−4b=a-3a + 6b - 4b = a
  2. Combine like terms: Combine like terms to simplify the equation. −3a+2b=a-3a + 2b = a
  3. Move term involving a: Now, move the term involving a on the left side to the right side by adding 33a to both sides of the equation.\newline22b = a + 33a
  4. Combine terms involving a: Combine the terms on the right side to get a single term involving a.\newline22b = 44a
  5. Divide both sides: Divide both sides by 22 to solve for bb.\newlineb=4a2b = \frac{4a}{2}
  6. Simplify the formula: Simplify the right side to get the final formula for bb in terms of aa.\newlineb=2ab = 2a

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