Use the quadratic formula to solve. Express your answer in simplest form. q^(2)+10 q+25=0 Answer: q=

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Use the quadratic formula to solve. Express your answer in simplest form.  q^(2)+10 q+25=0 Answer:  q=

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Quadratic Formula: The quadratic formula is given by q = (-b ± √(b^2 - 4ac)) / (2a), where a, b, and c are the coefficients of the quadratic equation ax^2 + bx + c = 0. In this case, a = 1, b = 10, and c = 25.Calculate Discriminant: First, we calculate the discriminant, which is the part under the square root in the quadratic formula: b^2 - 4ac. For our equation, the discriminant is 10^2 - 4(1)(25).Discriminant Calculation: Calculating the discriminant: 10^2 - 4(1)(25) = 100 - 100 = 0.Apply Quadratic Formula: Since the discriminant is 0, the equation has one real root (a repeated root). We can now apply the quadratic formula with the discriminant: q = (-b ± √(0)) / (2a).Plug in Values: Plugging in the values of a and b into the formula: q = (-10 ± √(0)) / (2*1).Simplify Expression: Simplifying the expression: q = (-10 ± 0) / 2 = -10 / 2.Final Solution: The final solution is q = -5. Since the discriminant was 0, this is the only solution.

Use the quadratic formula to solve. Express your answer in simplest form. $\newline$ $q^{2}+10 q+25=0$ $\newline$ Answer: $q=$

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Use the quadratic formula to solve. Express your answer in simplest form.\newlineq2+10q+25=0 q^{2}+10 q+25=0 q2+10q+25=0\newlineAnswer: q= q= q=

Use the quadratic formula to solve. Express your answer in simplest form. $\newline$ $q^{2}+10 q+25=0$ $\newline$ Answer: $q=$