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Let’s check out your problem:
Use the imaginary number
i
i
i
to rewrite the expression below as a complex number. Simplify all radicals.
−
−
88
-\sqrt{-88}
−
−
88
View step-by-step help
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Math Problems
Algebra 2
Introduction to complex numbers
Full solution
Q.
Use the imaginary number
i
i
i
to rewrite the expression below as a complex number. Simplify all radicals.
−
−
88
-\sqrt{-88}
−
−
88
Breakdown of expression:
First, let's break
−
−
88
-\sqrt{-88}
−
−
88
into
−
−
1
×
88
-\sqrt{-1 \times 88}
−
−
1
×
88
.
Use of imaginary unit:
Now, we know that
−
1
\sqrt{-1}
−
1
is the imaginary unit
i
i
i
, so we can write
−
−
1
×
88
-\sqrt{-1 \times 88}
−
−
1
×
88
as
−
i
×
88
-i \times \sqrt{88}
−
i
×
88
.
Simplify
88
\sqrt{88}
88
:
Next, we simplify
88
\sqrt{88}
88
by finding the prime
factors
of
88
88
88
, which are
2
2
2
,
2
2
2
,
2
2
2
, and
11
11
11
. So,
88
\sqrt{88}
88
is
2
3
×
11
\sqrt{2^3 \times 11}
2
3
×
11
.
Factorize
88
\sqrt{88}
88
:
We can take out a pair of
2
2
2
s from under the radical as a single
2
2
2
, so
2
3
×
11
\sqrt{2^3 \times 11}
2
3
×
11
becomes
2
×
2
×
11
2 \times \sqrt{2 \times 11}
2
×
2
×
11
.
Final simplification:
Now we have
−
i
×
2
×
2
×
11
-i \times 2 \times \sqrt{2 \times 11}
−
i
×
2
×
2
×
11
, which simplifies to
−
2
i
×
22
-2i \times \sqrt{22}
−
2
i
×
22
.
More problems from Introduction to complex numbers
Question
Simplify.
\newline
8
i
+
6
i
8i + 6i
8
i
+
6
i
\newline
\newline
Write your answer in the form
a
+
b
i
a + bi
a
+
bi
.
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Find the complex conjugate of the given number.
\newline
4
+
10
i
4 + 10i
4
+
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i
\newline
\newline
Write your answer in the form
a
+
b
i
a + bi
a
+
bi
.
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Question
Simplify.
\newline
−
4
i
−
9
i
\frac{{-4i}}{{-9i}}
−
9
i
−
4
i
\newline
\newline
Write your simplified answer in the form
a
+
b
i
a + bi
a
+
bi
.
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Question
Combine the like terms to create an equivalent expression.
\newline
7
k
−
k
+
19
=
0
7k-k+19=\boxed{\phantom{0}}
7
k
−
k
+
19
=
0
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Question
Apply the distributive property to factor out the greatest common factor.
\newline
9
+
12
n
=
9+12 n=
9
+
12
n
=
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Question
Solve the equation.
\newline
12
=
n
−
9
n
=
□
\begin{aligned} & 12=n-9 \\ n= & \square \end{aligned}
n
=
12
=
n
−
9
□
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Posted 1 year ago
Question
What is the amplitude of
y
=
−
sin
(
8
x
−
3
)
+
5
y=-\sin (8 x-3)+5
y
=
−
sin
(
8
x
−
3
)
+
5
?
\newline
units
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Posted 1 year ago
Question
What is the period of
\newline
y
=
4
sin
(
−
2
x
+
7
)
−
1
?
y=4 \sin (-2 x+7)-1 \text { ? }
y
=
4
sin
(
−
2
x
+
7
)
−
1
?
\newline
Give an exact value.
\newline
units
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Posted 1 year ago
Question
3
⋅
(
3
+
20
i
)
=
3 \cdot(3+20 i)=
3
⋅
(
3
+
20
i
)
=
\newline
Your answer should be a complex number in the form
a
+
b
i
a+b i
a
+
bi
where
a
a
a
and
b
b
b
are real numbers.
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Posted 1 year ago
Question
(
35
−
23
i
)
+
(
13
+
25
i
)
=
(35-23 i)+(13+25 i)=
(
35
−
23
i
)
+
(
13
+
25
i
)
=
\newline
Express your answer in the form
(
a
+
b
i
)
(a+b i)
(
a
+
bi
)
.
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Posted 1 year ago
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