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Use the following function rule to find f(0)f(0).\newlinef(x)=8(12)x+12f(x) = 8(12)^x + 12\newlinef(0)=f(0) = _____\_\_\_\_\_

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Q. Use the following function rule to find f(0)f(0).\newlinef(x)=8(12)x+12f(x) = 8(12)^x + 12\newlinef(0)=f(0) = _____\_\_\_\_\_
  1. Identify Function for f(0)f(0): Identify the function which represents f(0)f(0). Substitute in 00 for xx in f(x)=8(12)x+12f(x) = 8(12)^x + 12. f(0)=8(12)0+12f(0) = 8(12)^0 + 12
  2. Substitute xx in f(x)f(x): Evaluate 8(12)08(12)^0.\newlineSince any number raised to the power of 00 is 11, 120=112^0 = 1.\newline8(12)0=8×18(12)^0 = 8 \times 1\newline8(12)0=88(12)^0 = 8
  3. Evaluate 8(12)08(12)^0: f(0)=8+12f(0) = 8 + 12\newlineDetermine the value of f(0)f(0).\newlinef(0)=8+12f(0) = 8 + 12\newlinef(0)=20f(0) = 20

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