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Use the following function rule to find f(0)f(0).\newlinef(x)=5(5)x+6f(x) = 5(5)^x + 6\newlinef(0)=‾f(0) = \underline{\hspace{3em}}

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Q. Use the following function rule to find f(0)f(0).\newlinef(x)=5(5)x+6f(x) = 5(5)^x + 6\newlinef(0)=‾f(0) = \underline{\hspace{3em}}
  1. Identify Function: Identify the function which represents f(0)f(0).\newlineSubstitute in 00 for xx in f(x)=5(5)x+6f(x) = 5(5)^x + 6.\newlinef(0)=5(5)0+6f(0) = 5(5)^0 + 6
  2. Substitute and Simplify: Evaluate 5(5)05(5)^0.\newlineSince any number to the power of 00 is 11, we have:\newline5(5)05(5)^0\newline=5×1= 5 \times 1\newline=5= 5
  3. Evaluate Exponential: f(0)=5+6f(0) = 5 + 6\newlineDetermine the value of f(0)f(0).\newlinef(0)=5+6f(0) = 5 + 6 \newlinef(0)=11f(0) = 11

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