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Use the following function rule to find f(0)f(0).\newlinef(x)=12(5)x+6f(x) = 12(5)^x + 6\newlinef(0)=f(0) = _____

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Q. Use the following function rule to find f(0)f(0).\newlinef(x)=12(5)x+6f(x) = 12(5)^x + 6\newlinef(0)=f(0) = _____
  1. Identify Function for f(0)f(0): Identify the function which represents f(0)f(0). Substitute in 00 for xx in f(x)=12(5)x+6f(x) = 12(5)^x + 6. f(0)=12(5)0+6f(0) = 12(5)^0 + 6
  2. Substitute xx in f(x)f(x): Evaluate 12(5)012(5)^0.\newlineSince any number raised to the power of 00 is 11, 12(5)012(5)^0 simplifies to 12×112 \times 1.\newline12(5)012(5)^0\newline=12×1= 12 \times 1\newline=12= 12
  3. Evaluate 12(5)012(5)^0: f(0)=12+6f(0) = 12 + 6\newlineDetermine the value of f(0)f(0).\newlinef(0)=12+6f(0) = 12 + 6\newlinef(0)=18f(0) = 18

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