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Let’s check out your problem:
Use the Binomial Theorem to complete the expansion of
(
x
+
2
)
4
(x + 2)^4
(
x
+
2
)
4
.
x
4
+
8
x
3
+
24
x
2
+
32
x
+
‾
x^4 + 8x^3 + 24x^2 + 32x + \underline{\hspace{1cm}}
x
4
+
8
x
3
+
24
x
2
+
32
x
+
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Math Problems
Precalculus
Binomial Theorem II
Full solution
Q.
Use the Binomial Theorem to complete the expansion of
(
x
+
2
)
4
(x + 2)^4
(
x
+
2
)
4
.
x
4
+
8
x
3
+
24
x
2
+
32
x
+
‾
x^4 + 8x^3 + 24x^2 + 32x + \underline{\hspace{1cm}}
x
4
+
8
x
3
+
24
x
2
+
32
x
+
Identify general term:
Identify the general term in the binomial expansion:
T
(
k
+
1
)
=
C
(
n
,
k
)
⋅
a
(
n
−
k
)
⋅
b
k
T(k+1) = C(n, k) \cdot a^{(n-k)} \cdot b^k
T
(
k
+
1
)
=
C
(
n
,
k
)
⋅
a
(
n
−
k
)
⋅
b
k
where
n
=
4
n=4
n
=
4
,
a
=
x
a=x
a
=
x
, and
b
=
2
b=2
b
=
2
.
Calculate missing term:
Calculate the missing term, which is the constant term when
k
=
4
k=4
k
=
4
:
T
(
5
)
=
C
(
4
,
4
)
⋅
x
(
4
−
4
)
⋅
2
4
T(5) = C(4, 4) \cdot x^{(4-4)} \cdot 2^4
T
(
5
)
=
C
(
4
,
4
)
⋅
x
(
4
−
4
)
⋅
2
4
.
Perform calculations:
Perform the calculations:
C
(
4
,
4
)
=
1
C(4, 4) = 1
C
(
4
,
4
)
=
1
,
x
0
=
1
x^0 = 1
x
0
=
1
, and
2
4
=
16
2^4 = 16
2
4
=
16
. So,
T
(
5
)
=
1
×
1
×
16
=
16
T(5) = 1 \times 1 \times 16 = 16
T
(
5
)
=
1
×
1
×
16
=
16
.
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(
9
a
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−
(
2
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9
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(
3
y
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)
2
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(
3
y
+
2
)
2
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Question
Divide. If there is a remainder, include it as a simplified fraction.
\newline
(
24
t
2
+
36
t
)
÷
6
t
(24t^2 + 36t) \div 6t
(
24
t
2
+
36
t
)
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t
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Question
Is the function
q
(
x
)
=
x
6
−
9
q(x) = x^6 - 9
q
(
x
)
=
x
6
−
9
even, odd, or neither?
\newline
Choices:
\newline
[[even][odd][neither]]
\text{[[even][odd][neither]]}
[[even][odd][neither]]
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Question
Find the product. Simplify your answer.
\newline
−
3
q
2
(
−
3
q
2
+
q
)
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−
3
q
2
(
−
3
q
2
+
q
)
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Question
Find the product. Simplify your answer.
\newline
(
r
+
3
)
(
4
r
+
2
)
(r + 3)(4r + 2)
(
r
+
3
)
(
4
r
+
2
)
\newline
______
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Question
Find the roots of the factored polynomial.
\newline
(
x
+
7
)
(
x
+
4
)
(x + 7)(x + 4)
(
x
+
7
)
(
x
+
4
)
\newline
Write your answer as a list of values separated by commas.
\newline
x
=
x =
x
=
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