Use synthetic division to find (x2+6x−18)÷(x−3).Write your answer in the form q(x)+d(x)r, where q(x) is a polynomial, r is an integer, and d(x) is a linear polynomial. Simplify any fractions._________
Q. Use synthetic division to find (x2+6x−18)÷(x−3).Write your answer in the form q(x)+d(x)r, where q(x) is a polynomial, r is an integer, and d(x) is a linear polynomial. Simplify any fractions._________
Set up synthetic division: Set up synthetic division with 3 as the root from (x−3) and the coefficients of the polynomial x2+6x−18, which are 1, 6, and −18.
Bring down leading coefficient: Bring down the leading coefficient, which is 1.
Multiply root by leading coefficient: Multiply the root, which is 3, by the leading coefficient, 1, and write the result, 3, under the second coefficient, 6.
Add second coefficient and result: Add the second coefficient, 6, and the result from the previous step, 3, to get 9. Write this under the line.
Multiply root by new number: Multiply the root, 3, by the new number, 9, and write the result, 27, under the third coefficient, −18.
Add third coefficient and result: Add the third coefficient, −18, and the result from the previous step, 27, to get 9. Write this under the line; this is the remainder.
Identify quotient and remainder: The numbers on the bottom line are the coefficients of the quotient polynomial q(x), and the last number is the remainder. So, q(x)=x+9 and the remainder is 9.
Write final answer in form: Write the final answer in the form q(x)+d(x)r. The quotient polynomial is x+9, the remainder is 9, and the divisor is x−3. So, the final answer is (x+9)+(x−3)9.
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