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Use Pascal's Triangle to expand 
(3z^(2)-4)^(3). Express your answer in simplest form.
Answer:

Use Pascal's Triangle to expand (3z24)3 \left(3 z^{2}-4\right)^{3} . Express your answer in simplest form.\newlineAnswer:

Full solution

Q. Use Pascal's Triangle to expand (3z24)3 \left(3 z^{2}-4\right)^{3} . Express your answer in simplest form.\newlineAnswer:
  1. Identify Row: Identify the row of Pascal's Triangle that corresponds to the exponent of the binomial expansion.\newlineSince we are expanding (3z24)3(3z^{2}-4)^{3}, we need the fourth row of Pascal's Triangle (since the rows are indexed starting from 00). The fourth row of Pascal's Triangle is 1,3,3,11, 3, 3, 1.
  2. Write Expansion Terms: Write out each term of the expansion using the coefficients from Pascal's Triangle.\newlineThe expansion will have four terms, corresponding to the coefficients 1,3,3,11, 3, 3, 1. Each term will be of the form (coefficient)×(first term in the binomial raised to a power)×(second term in the binomial raised to a power)(\text{coefficient}) \times (\text{first term in the binomial raised to a power}) \times (\text{second term in the binomial raised to a power}). The powers on the first term will decrease from 33 to 00, and the powers on the second term will increase from 00 to 33.
  3. Calculate First Term: Calculate the first term of the expansion.\newlineUsing the first coefficient from Pascal's Triangle, which is 11, the first term is (1)×(3z2)3×(4)0(1) \times (3z^{2})^{3} \times (-4)^{0}. This simplifies to (1)×(27z6)×(1)(1) \times (27z^{6}) \times (1), which is just 27z627z^{6}.
  4. Calculate Second Term: Calculate the second term of the expansion.\newlineUsing the second coefficient from Pascal's Triangle, which is 33, the second term is (3)×(3z2)2×(4)1(3) \times (3z^{2})^{2} \times (-4)^{1}. This simplifies to (3)×(9z4)×(4)(3) \times (9z^{4}) \times (-4), which is 108z4-108z^{4}.
  5. Calculate Third Term: Calculate the third term of the expansion.\newlineUsing the third coefficient from Pascal's Triangle, which is 33, the third term is (3)×(3z2)1×(4)2(3) \times (3z^{2})^{1} \times (-4)^{2}. This simplifies to (3)×(3z2)×(16)(3) \times (3z^{2}) \times (16), which is 144z2144z^{2}.
  6. Calculate Fourth Term: Calculate the fourth term of the expansion.\newlineUsing the fourth coefficient from Pascal's Triangle, which is 11, the fourth term is (1)×(3z2)0×(4)3(1) \times (3z^{2})^{0} \times (-4)^{3}. This simplifies to (1)×(1)×(64)(1) \times (1) \times (-64), which is 64-64.
  7. Combine Terms: Combine all the terms to write the final expanded form.\newlineThe expanded form of (3z24)3(3z^{2}-4)^{3} is 27z6108z4+144z26427z^{6} - 108z^{4} + 144z^{2} - 64.

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