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Use Pascal's Triangle to expand 
(2y+x)^(5). Express your answer in simplest form.
Answer:

Use Pascal's Triangle to expand (2y+x)5 (2 y+x)^{5} . Express your answer in simplest form.\newlineAnswer:

Full solution

Q. Use Pascal's Triangle to expand (2y+x)5 (2 y+x)^{5} . Express your answer in simplest form.\newlineAnswer:
  1. Identify 55th Row: Identify the 55th row of Pascal's Triangle to determine the coefficients for the expansion of (2y+x)5(2y+x)^{5}. The 55th row of Pascal's Triangle is 1,5,10,10,5,11, 5, 10, 10, 5, 1.
  2. Write Expansion Terms: Write out the terms of the expansion using the binomial theorem and the coefficients from Pascal's Triangle.\newlineThe expansion will have terms of the form: coefficient×(2y)5k×xk\text{coefficient} \times (2y)^{5-k} \times x^k, where kk ranges from 00 to 55.
  3. Calculate Each Term: Calculate each term of the expansion using the coefficients and the powers of 2y2y and xx. The terms are: 1×(2y)5×x0=32y51 \times (2y)^5 \times x^0 = 32y^5 5×(2y)4×x1=80y4x5 \times (2y)^4 \times x^1 = 80y^4x 10×(2y)3×x2=80y3x210 \times (2y)^3 \times x^2 = 80y^3x^2 10×(2y)2×x3=40y2x310 \times (2y)^2 \times x^3 = 40y^2x^3 5×(2y)1×x4=10yx45 \times (2y)^1 \times x^4 = 10yx^4 $\(1\) \times (\(2\)y)^\(0\) \times x^\(5\) = x^\(5\)
  4. Combine Terms: Combine all the terms to write the expanded form of \((2y+x)^{5}\). The expanded form is: \(32y^{5} + 80y^{4}x + 80y^{3}x^{2} + 40y^{2}x^{3} + 10yx^{4} + x^{5}\)

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