Use Pascal's Triangle to expand (2y^(2)+z^(2))^(3). Express your answer in simplest form. Answer:

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Use Pascal's Triangle to expand  (2y^(2)+z^(2))^(3). Express your answer in simplest form. Answer:

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Identify Row: Identify the row of Pascal's Triangle that corresponds to the exponent of the binomial expansion. Since we are expanding (2y^(2)+z^(2))^(3), we need to look at the fourth row of Pascal's Triangle, which corresponds to the coefficients for a cubic expansion. The fourth row of Pascal's Triangle is 1, 3, 3, 1.Write Terms: Write out each term of the expansion using the coefficients from Pascal's Triangle. The expansion will have four terms, and the coefficients will be 1, 3, 3, and 1, respectively. The terms will be: 1*(2y^(2))^3*(z^(2))^0, 3*(2y^(2))^2*(z^(2))^1, 3*(2y^(2))^1*(z^(2))^2, 1*(2y^(2))^0*(z^(2))^3.Calculate Each Term: Calculate each term of the expansion. Now we will calculate each term: 1*(2y^(2))^3*(z^(2))^0 = 1*(8y^(6))*(1) = 8y^(6), 3*(2y^(2))^2*(z^(2))^1 = 3*(4y^(4))*(z^(2)) = 12y^(4)z^(2), 3*(2y^(2))^1*(z^(2))^2 = 3*(2y^(2))*(z^(4)) = 6y^(2)z^(4), 1*(2y^(2))^0*(z^(2))^3 = 1*(1)*(z^(6)) = z^(6).Combine Final Form: Combine all the terms to write the final expanded form. The final expanded form of (2y^(2)+z^(2))^(3) is: 8y^(6) + 12y^(4)z^(2) + 6y^(2)z^(4) + z^(6).

Use Pascal's Triangle to expand $\left(2 y^{2}+z^{2}\right)^{3}$ . Express your answer in simplest form. $\newline$ Answer:

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Use Pascal's Triangle to expand (2y2+z2)3 \left(2 y^{2}+z^{2}\right)^{3} (2y2+z2)3. Express your answer in simplest form.\newlineAnswer:

Use Pascal's Triangle to expand $\left(2 y^{2}+z^{2}\right)^{3}$ . Express your answer in simplest form. $\newline$ Answer: