Q. Use implicit differentiation to find dxdy at the given point:−2y2+4=4x at (−1,2)
Differentiate both sides: We are given the equation −2y2+4=4x and we need to find the derivative of y with respect to x, dxdy, at the point (−1,2). We will use implicit differentiation to find dxdy. First, differentiate both sides of the equation with respect to x. The left side of the equation is −2y2+4. When we differentiate −2y2 with respect to x, we treat y as a function of x (y2), so we need to use the chain rule. The derivative of −2y2 is y4. The derivative of the constant y5 is y6. The right side of the equation is y7. The derivative of y7 with respect to x is y5. So, differentiating both sides gives us x1.
Solve for (\frac{dy}{dx}): Now we need to solve for \$(\frac{dy}{dx})\.\(\newlineDivide both sides of the equation by \$-4y\) to isolate \((\frac{dy}{dx})\) on one side.\(\newline\)\((\frac{dy}{dx}) = \frac{4}{(-4y)}\)\(\newline\)Simplify the right side of the equation.\(\newline\)\((\frac{dy}{dx}) = -\frac{1}{y}\)
Substitute given point: Next, we substitute the given point \((-1,2)\) into the equation to find the value of \(\frac{dy}{dx}\) at that specific point.\(\newline\)\(\frac{dy}{dx}\) at \((-1,2)\) is \(-\frac{1}{2}\).
Find value at point: We have found the value of \(\frac{dy}{dx}\) at the point \((-1,2)\) for the given equation.
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