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Use implicit differentiation to find dydx\frac{dy}{dx} at the given point:\newline2y2+4=4x-2y^{2}+4=4x at (1,2)(-1,2)

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Q. Use implicit differentiation to find dydx\frac{dy}{dx} at the given point:\newline2y2+4=4x-2y^{2}+4=4x at (1,2)(-1,2)
  1. Differentiate both sides: We are given the equation 2y2+4=4x-2y^2 + 4 = 4x and we need to find the derivative of yy with respect to xx, dydx\frac{dy}{dx}, at the point (1,2)(-1,2). We will use implicit differentiation to find dydx\frac{dy}{dx}. First, differentiate both sides of the equation with respect to xx. The left side of the equation is 2y2+4-2y^2 + 4. When we differentiate 2y2-2y^2 with respect to xx, we treat yy as a function of xx (yy22), so we need to use the chain rule. The derivative of 2y2-2y^2 is yy44. The derivative of the constant yy55 is yy66. The right side of the equation is yy77. The derivative of yy77 with respect to xx is yy55. So, differentiating both sides gives us xx11.
  2. Solve for (\frac{dy}{dx}): Now we need to solve for \$(\frac{dy}{dx})\.\(\newlineDivide both sides of the equation by \$-4y\) to isolate \((\frac{dy}{dx})\) on one side.\(\newline\)\((\frac{dy}{dx}) = \frac{4}{(-4y)}\)\(\newline\)Simplify the right side of the equation.\(\newline\)\((\frac{dy}{dx}) = -\frac{1}{y}\)
  3. Substitute given point: Next, we substitute the given point \((-1,2)\) into the equation to find the value of \(\frac{dy}{dx}\) at that specific point.\(\newline\)\(\frac{dy}{dx}\) at \((-1,2)\) is \(-\frac{1}{2}\).
  4. Find value at point: We have found the value of \(\frac{dy}{dx}\) at the point \((-1,2)\) for the given equation.

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