The function f is defined by f(x)=x2+x−2sin(2x). Use a calculator to write the equation of the line tangent to the graph of f when x=3. You should round all decimals to 3 places.Answer:
Q. The function f is defined by f(x)=x2+x−2sin(2x). Use a calculator to write the equation of the line tangent to the graph of f when x=3. You should round all decimals to 3 places.Answer:
Calculate Derivative and Slope: To find the equation of the tangent line at x=3, we first need to calculate the derivative of the function f(x) to find the slope of the tangent line at that point.The derivative of f(x)=x2+x−2sin(2x) is f′(x)=2x+1−4cos(2x).Now we will calculate f′(3) to get the slope of the tangent line at x=3.
Calculate f′(3): Using a calculator, we find the value of f′(3)=2(3)+1−4cos(2×3). This gives us f′(3)=6+1−4cos(6). Now we will calculate the numerical value of cos(6) and then find the value of f′(3).
Find y-coordinate at x=3: Assuming the calculator is set to radian mode, we find that cos(6)≈0.960 (rounded to three decimal places).Now we calculate f′(3)=6+1−4(0.960).This gives us f′(3)=7−3.840=3.160 (rounded to three decimal places).The slope of the tangent line at x=3 is 3.160.
Use Point-Slope Form: Next, we need to find the y-coordinate of the point on the graph of f(x) at x=3 to use it in the point-slope form of the equation of the tangent line.We calculate f(3)=32+3−2sin(2⋅3).
Write Equation in Slope-Intercept Form: Using the calculator, we find that sin(6)≈−0.279 (rounded to three decimal places).Now we calculate f(3)=9+3−2(−0.279).This gives us f(3)=12+0.558=12.558 (rounded to three decimal places).The y-coordinate of the point on the graph of f(x) at x=3 is 12.558.
Write Equation in Slope-Intercept Form: Using the calculator, we find that sin(6)≈−0.279 (rounded to three decimal places). Now we calculate f(3)=9+3−2(−0.279). This gives us f(3)=12+0.558=12.558 (rounded to three decimal places). The y-coordinate of the point on the graph of f(x) at x=3 is 12.558.We now have the slope of the tangent line (m=3.160) and a point on the tangent line (3,12.558). Using the point-slope form of the equation of a line, y−y1=m(x−x1), we can write the equation of the tangent line. Substituting the values, we get f(3)=9+3−2(−0.279)0.
Write Equation in Slope-Intercept Form: Using the calculator, we find that sin(6)≈−0.279 (rounded to three decimal places). Now we calculate f(3)=9+3−2(−0.279). This gives us f(3)=12+0.558=12.558 (rounded to three decimal places). The y-coordinate of the point on the graph of f(x) at x=3 is 12.558.We now have the slope of the tangent line (m=3.160) and a point on the tangent line (3,12.558). Using the point-slope form of the equation of a line, y−y1=m(x−x1), we can write the equation of the tangent line. Substituting the values, we get f(3)=9+3−2(−0.279)0.To write the equation in slope-intercept form, we simplify the equation: f(3)=9+3−2(−0.279)1. Expanding this, we get f(3)=9+3−2(−0.279)2. Finally, we combine like terms to get f(3)=9+3−2(−0.279)3. This is the equation of the tangent line to the graph of f(x) at x=3, rounded to three decimal places.
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