Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Two rental car companies are running specials this month. At Rob's Rentals, customers will pay $50\$50 to rent a mid-sized car for the first day, plus $4\$4 for each additional day. At Washington Rent-a-Car, the price for a mid-sized car is $60\$60 for the first day and $3\$3 for every additional day beyond that. At some point, renting from either one of the companies would cost a customer the same amount. How many additional days would that take?\newlineWrite a system of equations, graph them, and type the solution.\newline____ additional days\newline

Full solution

Q. Two rental car companies are running specials this month. At Rob's Rentals, customers will pay $50\$50 to rent a mid-sized car for the first day, plus $4\$4 for each additional day. At Washington Rent-a-Car, the price for a mid-sized car is $60\$60 for the first day and $3\$3 for every additional day beyond that. At some point, renting from either one of the companies would cost a customer the same amount. How many additional days would that take?\newlineWrite a system of equations, graph them, and type the solution.\newline____ additional days\newline
  1. Set up equations: Let's set up the equations for both rental companies. For Rob's Rentals, the cost CC after dd additional days is given by C=50+4dC = 50 + 4d. For Washington Rent-a-Car, the cost CC is C=60+3dC = 60 + 3d.
  2. Equate expressions: To find when the costs are the same, we equate the two expressions: 50+4d=60+3d50 + 4d = 60 + 3d.
  3. Solve for d: Solve for d: Subtract 3d3d from both sides to get 4d3d=60504d - 3d = 60 - 50, which simplifies to d=10d = 10.

More problems from Mean, variance, and standard deviation of binomial distributions