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This season, the probability that the Yankees will win a game is 0.52 and the probability that the Yankees will score 5 or more runs in a game is 0.56 . The probability that the Yankees win and score 5 or more runs is 0.4 . What is the probability that the Yankees would score fewer than 5 runs when they lose the game? Round your answer to the nearest thousandth.
Answer:

This season, the probability that the Yankees will win a game is 00.5252 and the probability that the Yankees will score 55 or more runs in a game is 00.5656 . The probability that the Yankees win and score 55 or more runs is 00.44 . What is the probability that the Yankees would score fewer than 55 runs when they lose the game? Round your answer to the nearest thousandth.\newlineAnswer:

Full solution

Q. This season, the probability that the Yankees will win a game is 00.5252 and the probability that the Yankees will score 55 or more runs in a game is 00.5656 . The probability that the Yankees win and score 55 or more runs is 00.44 . What is the probability that the Yankees would score fewer than 55 runs when they lose the game? Round your answer to the nearest thousandth.\newlineAnswer:
  1. Define Events: Let's denote the events as follows:\newlineW: The Yankees win a game.\newlineS: The Yankees score 55 or more runs in a game.\newlineWe are given the following probabilities:\newlineP(W)=0.52P(W) = 0.52\newlineP(S)=0.56P(S) = 0.56\newlineP(W and S)=0.4P(W \text{ and } S) = 0.4\newlineWe need to find the probability that the Yankees score fewer than 55 runs when they lose, which can be denoted as P(SW)P(S' | W'), where SS' is the complement of SS (scoring fewer than 55 runs) and WW' is the complement of WW (losing the game).
  2. Calculate Probabilities: First, we need to find the probability that the Yankees lose a game, which is the complement of the probability that they win. This can be calculated as:\newlineP(W)=1P(W)P(W') = 1 - P(W)\newlineP(W)=10.52P(W') = 1 - 0.52\newlineP(W)=0.48P(W') = 0.48
  3. Find Probability of Losing and Scoring Fewer Runs: Next, we need to find the probability that the Yankees score fewer than 55 runs, which is the complement of the probability that they score 55 or more runs. This can be calculated as:\newlineP(S)=1P(S)P(S') = 1 - P(S)\newlineP(S)=10.56P(S') = 1 - 0.56\newlineP(S)=0.44P(S') = 0.44
  4. Calculate Conditional Probability: Now, we need to find the probability that the Yankees lose and score fewer than 55 runs, which is P(W and S)P(W' \text{ and } S'). We can use the complement of the probability that they win and score 55 or more runs to find this. This can be calculated as:\newlineP(W and S)=P(S)P(W and S)P(W' \text{ and } S') = P(S') - P(W \text{ and } S)\newlineP(W and S)=0.440.4P(W' \text{ and } S') = 0.44 - 0.4\newlineP(W and S)=0.04P(W' \text{ and } S') = 0.04
  5. Calculate Conditional Probability: Now, we need to find the probability that the Yankees lose and score fewer than 55 runs, which is P(W and S)P(W' \text{ and } S'). We can use the complement of the probability that they win and score 55 or more runs to find this. This can be calculated as:\newlineP(W and S)=P(S)P(W and S)P(W' \text{ and } S') = P(S') - P(W \text{ and } S)\newlineP(W and S)=0.440.4P(W' \text{ and } S') = 0.44 - 0.4\newlineP(W and S)=0.04P(W' \text{ and } S') = 0.04Finally, we can find the probability that the Yankees score fewer than 55 runs given that they lose the game using the conditional probability formula:\newlineP(SW)=P(W and S)P(W)P(S' | W') = \frac{P(W' \text{ and } S')}{P(W')}\newlineP(SW)=0.040.48P(S' | W') = \frac{0.04}{0.48}\newlineP(SW)0.0833P(S' | W') \approx 0.0833 (rounded to the nearest thousandth)

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