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This season, the probability that the Yankees will win a game is 0.61 and the probability that the Yankees will score 5 or more runs in a game is 0.43 . The probability that the Yankees win and score 5 or more runs is 0.36 . What is the probability that the Yankees will lose when they score fewer than 5 runs? Round your answer to the nearest thousandth.
Answer:

This season, the probability that the Yankees will win a game is 00.6161 and the probability that the Yankees will score 55 or more runs in a game is 00.4343 . The probability that the Yankees win and score 55 or more runs is 00.3636 . What is the probability that the Yankees will lose when they score fewer than 55 runs? Round your answer to the nearest thousandth.\newlineAnswer:

Full solution

Q. This season, the probability that the Yankees will win a game is 00.6161 and the probability that the Yankees will score 55 or more runs in a game is 00.4343 . The probability that the Yankees win and score 55 or more runs is 00.3636 . What is the probability that the Yankees will lose when they score fewer than 55 runs? Round your answer to the nearest thousandth.\newlineAnswer:
  1. Denote Events: Let's denote the events as follows:\newlineW: The Yankees win a game.\newlineS: The Yankees score 55 or more runs in a game.\newlineWe are given the following probabilities:\newlineP(W)=0.61P(W) = 0.61\newlineP(S)=0.43P(S) = 0.43\newlineP(W and S)=0.36P(W \text{ and } S) = 0.36\newlineWe want to find the probability that the Yankees lose and score fewer than 55 runs. Let's denote this event as L (Yankees lose) and F (Yankees score fewer than 55 runs).\newlineFirst, we need to find the probability that the Yankees lose a game, which is the complement of the probability that they win. We can calculate this using the formula:\newlineP(L)=1P(W)P(L) = 1 - P(W)
  2. Calculate Probability of Losing: Now, let's calculate the probability that the Yankees lose a game: \newlineP(L)=1P(W)P(L) = 1 - P(W)\newlineP(L)=10.61P(L) = 1 - 0.61\newlineP(L)=0.39P(L) = 0.39
  3. Calculate Probability of Scoring Fewer Runs: Next, we need to find the probability that the Yankees score fewer than 55 runs. This is the complement of the probability that they score 55 or more runs. We can calculate this using the formula:\newlineP(F)=1P(S)P(F) = 1 - P(S)
  4. Calculate Probability of Losing and Scoring Fewer Runs: Now, let's calculate the probability that the Yankees score fewer than 55 runs:\newlineP(F)=1P(S)P(F) = 1 - P(S)\newlineP(F)=10.43P(F) = 1 - 0.43\newlineP(F)=0.57P(F) = 0.57
  5. Round Final Answer: To find the probability that the Yankees lose and score fewer than 55 runs, we need to use the Multiplication Rule of Probability for independent events. However, we must first ensure that the events LL and FF are independent. Since we are not given any information about their dependence, we will assume they are independent for this calculation. The formula is:\newlineP(L and F)=P(L)×P(F)P(L \text{ and } F) = P(L) \times P(F)
  6. Round Final Answer: To find the probability that the Yankees lose and score fewer than 55 runs, we need to use the Multiplication Rule of Probability for independent events. However, we must first ensure that the events LL and FF are independent. Since we are not given any information about their dependence, we will assume they are independent for this calculation. The formula is:\newlineP(L and F)=P(L)×P(F)P(L \text{ and } F) = P(L) \times P(F)Now, let's calculate the probability that the Yankees lose and score fewer than 55 runs:\newlineP(L and F)=P(L)×P(F)P(L \text{ and } F) = P(L) \times P(F)\newlineP(L and F)=0.39×0.57P(L \text{ and } F) = 0.39 \times 0.57\newlineP(L and F)=0.2223P(L \text{ and } F) = 0.2223
  7. Round Final Answer: To find the probability that the Yankees lose and score fewer than 55 runs, we need to use the Multiplication Rule of Probability for independent events. However, we must first ensure that the events LL and FF are independent. Since we are not given any information about their dependence, we will assume they are independent for this calculation. The formula is:\newlineP(L and F)=P(L)×P(F)P(L \text{ and } F) = P(L) \times P(F)Now, let's calculate the probability that the Yankees lose and score fewer than 55 runs:\newlineP(L and F)=P(L)×P(F)P(L \text{ and } F) = P(L) \times P(F)\newlineP(L and F)=0.39×0.57P(L \text{ and } F) = 0.39 \times 0.57\newlineP(L and F)=0.2223P(L \text{ and } F) = 0.2223Finally, we round the answer to the nearest thousandth as requested:\newlineP(L and F)0.222P(L \text{ and } F) \approx 0.222

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