Q. There are 16 students in a homeroom. How many different ways can they be chosen to be elected President, Vice President, and Treasurer?Answer:
Understand the Problem: Understand the problem.We need to find the number of different ways to choose 3 students from a group of 16 for the positions of President, Vice President, and Treasurer. This is a permutation problem because the order in which we choose the students matters (choosing student A for President and student B for Vice President is different from choosing student B for President and student A for Vice President).
Set up the Formula: Set up the permutation formula.The number of ways to arrange n items in r specific places is given by the permutation formula, which is nPr=(n−r)!n! where "!" denotes factorial.
Apply the Formula: Apply the permutation formula.In this case, n=16 (the total number of students) and r=3 (the number of positions to fill). So we need to calculate 16P3.16P3=(16−3)!16!
Calculate Factorial Difference: Calculate the factorial difference. 16!/(16−3)! simplifies to 16!/13! because (16−3)=13.
Simplify the Expression: Simplify the expression.We can simplify 16!/13! by canceling out the common factorial terms.16!/13!=(16×15×14×13!)/13!The 13! in the numerator and denominator cancel out, leaving us with 16×15×14.
Perform the Multiplication: Perform the multiplication.Now we multiply the remaining numbers.16×15×14=240×14=3360
Conclude with Answer: Conclude with the final answer.There are 3360 different ways for the 16 students to be chosen for the positions of President, Vice President, and Treasurer.