The sum of the ages of a man and his wife is \(81 years. The ratio of their ages is 5:4. Find the age of the younger person.A. 30 yearsB. 36 yearsC. 45 yearsD. 51 years
Q. The sum of the ages of a man and his wife is \(81 years. The ratio of their ages is 5:4. Find the age of the younger person.A. 30 yearsB. 36 yearsC. 45 yearsD. 51 years
Denote ages as variables: Let's denote the age of the man as 5x and the age of his wife as 4x, where x is a common multiplier.The ratio of their ages is given as 5:4, which means for every 5 units of age the man has, the wife has 4 units of the same age.
Write sum equation: We know that the sum of their ages is 81 years. So we can write the equation:5x+4x=81
Combine like terms: Combine like terms to solve for x.9x=81
Find value of x: Divide both sides of the equation by 9 to find the value of x.x=981x=9
Calculate age of younger person: Now that we have the value of x, we can find the age of the younger person, which is the wife with the age of 4x.Age of the younger person (wife) = 4×9
Calculate age of younger person: Now that we have the value of x, we can find the age of the younger person, which is the wife with the age of 4x.Age of the younger person (wife) = 4×9Calculate the age of the younger person.Age of the younger person = 36 years
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