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The speed of sound in air is about 332 meters per second ((m)/(s)) at 0 degrees Celsius (^(@)C). If the speed increases by 0.6(m)/(s) for every increase in temperature of 1^(@)C, which inequality best represents the temperatures, T, in degrees Celsius, for which the speed of sound in air exceeds 350(m)/(s) ? Choose 1 answer: (A) T < 30 (B) T <= 30 (C) T > 30 (D) T >= 30

The speed of sound in air is about 332ms332\frac{m}{s} at 0∘C0^\circ C. If the speed increases by 0.6ms0.6\frac{m}{s} for every increase in temperature of 1∘C1^\circ C, which inequality best represents the temperatures, TT, in degrees Celsius, for which the speed of sound in air exceeds 350ms350\frac{m}{s} ?\newlineChoose 11 answer:\newline(A) T < 30\newline(B) T≤30T \leq 30\newline(C) T > 30\newline(D) T≥30T \geq 30

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Q. The speed of sound in air is about 332ms332\frac{m}{s} at 0∘C0^\circ C. If the speed increases by 0.6ms0.6\frac{m}{s} for every increase in temperature of 1∘C1^\circ C, which inequality best represents the temperatures, TT, in degrees Celsius, for which the speed of sound in air exceeds 350ms350\frac{m}{s} ?\newlineChoose 11 answer:\newline(A) T<30T < 30\newline(B) T≤30T \leq 30\newline(C) T>30T > 30\newline(D) T≥30T \geq 30
  1. Given Information: We are given that the speed of sound in air at 00 degrees Celsius is 332332 meters per second. We are also told that the speed increases by 0.60.6 meters per second for every 11 degree Celsius increase in temperature. We need to find the temperature at which the speed of sound exceeds 350350 meters per second. Let's denote the temperature in degrees Celsius as TT.
  2. Equation Setup: First, we need to set up an equation that relates the speed of sound to the temperature. The speed of sound at any temperature TT can be represented as 332+0.6T332 + 0.6T, where 332332 is the speed of sound at 00 degrees Celsius and 0.6T0.6T is the increase in speed for TT degrees above 00 degrees Celsius.
  3. Inequality Setup: Next, we want to find the value of TT for which the speed of sound exceeds 350350 meters per second. So, we set up the inequality 332 + 0.6T > 350.
  4. Isolate T: Now, we solve the inequality for T. Subtract 332332 from both sides to isolate the term with TT on one side of the inequality: 0.6T > 350 - 332.
  5. Divide by 00.66: Perform the subtraction on the right side of the inequality: 0.6T > 18.
  6. Calculate T: Finally, divide both sides of the inequality by 0.60.6 to solve for TT: T > \frac{18}{0.6}.
  7. Calculate T: Finally, divide both sides of the inequality by 0.60.6 to solve for TT: T > \frac{18}{0.6}.Calculate the value of TT: T > 30.

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