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The perimeter of a rectangular hotel room is $50$ feet. It is $15$ feet long. How wide is it? $\newline$ $\newline$ $\_\_\_\_$ feet

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Area and perimeter: word problems

Full solution

Q. The perimeter of a rectangular hotel room is

50

feet. It is

15

feet long. How wide is it?

\newline

\newline

\_\_\_\_

feet

Perimeter Formula: Let $l$ be the length and $w$ be the width of the rectangle. $\newline$ The perimeter of a rectangle is given by the formula $P = 2l + 2w$ .
Substitution: Given the perimeter of the hotel room: $50$ feet and the length: $15$ feet. $\newline$ Substitute $50$ for $P$ and $15$ for $l$ in the formula $P = 2l + 2w$ . $\newline$ $50 = 2(15) + 2w$
Simplify Equation: Simplify the equation: $\newline$ $50 = 30 + 2w$ $\newline$ $50 - 30 = 2w$ $\newline$ $20 = 2w$
Solve for Width: Solve for $w$ : $\frac{20}{2} = w$ $10 = w$

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