Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

The number of barrels of oil a certain company exports annually increases at a rate that is proportional at any time to the number of barrels they export at that time.
The company exported 5.4 million barrels annually initially, and it exported 10.8 million barrels annually after 6 years.
How many million barrels of oil did the company export annually after 10 years?
Round to the nearest integer.
million barrels

The number of barrels of oil a certain company exports annually increases at a rate that is proportional at any time to the number of barrels they export at that time.\newlineThe company exported 55.44 million barrels annually initially, and it exported 1010.88 million barrels annually after 66 years.\newlineHow many million barrels of oil did the company export annually after 1010 years?\newlineRound to the nearest integer.\newline\square million barrels

Full solution

Q. The number of barrels of oil a certain company exports annually increases at a rate that is proportional at any time to the number of barrels they export at that time.\newlineThe company exported 55.44 million barrels annually initially, and it exported 1010.88 million barrels annually after 66 years.\newlineHow many million barrels of oil did the company export annually after 1010 years?\newlineRound to the nearest integer.\newline\square million barrels
  1. Identify growth type: Identify the type of growth. The problem states that the growth rate is proportional to the number of barrels exported at any time, which indicates exponential growth.
  2. Find initial value and factor: Determine the initial value aa and the growth factor bb. The initial value is the amount of oil exported initially, which is 5.45.4 million barrels. To find the growth factor, we need to use the information that after 66 years, the export amount doubled to 10.810.8 million barrels.
  3. Use exponential growth formula: Use the exponential growth formula to find the growth factor.\newlineThe exponential growth formula is P(t)=ab(t/T)P(t) = a \cdot b^{(t/T)}, where P(t)P(t) is the amount after time tt, aa is the initial amount, bb is the growth factor, and TT is the time it takes for the initial amount to grow by the factor bb.\newlineWe know that P(6)=10.8P(6) = 10.8 and a=5.4a = 5.4, so we can set up the equation 10.8=5.4b(6/T)10.8 = 5.4 \cdot b^{(6/T)}.
  4. Solve for growth factor: Solve for bb.\newlineDivide both sides by 5.45.4 to isolate b(6/T)b^{(6/T)} on one side:\newline10.85.4=b(6/T)\frac{10.8}{5.4} = b^{(6/T)}\newline2=b(6/T)2 = b^{(6/T)}\newlineSince the time it takes to double is 66 years, T=6T = 6.\newlineTherefore, b(6/6)=b1=2b^{(6/6)} = b^1 = 2.\newlineThis means the growth factor bb is 22.
  5. Find amount after 1010 years: Use the growth factor to find the amount after 1010 years.\newlineNow that we have the growth factor, we can use the formula P(t)=ab(t/T)P(t) = a \cdot b^{(t/T)} to find the amount after 1010 years.\newlineP(10)=5.42(10/6)P(10) = 5.4 \cdot 2^{(10/6)}
  6. Calculate the exponent: Calculate the exponent. \newline106\frac{10}{6} simplifies to 53\frac{5}{3}, so we need to calculate 2532^{\frac{5}{3}}.\newline2532^{\frac{5}{3}} is the cube root of 252^5, which is the cube root of 3232.
  7. Calculate final amount: Calculate the final amount.\newlineP(10)=5.4×253P(10) = 5.4 \times 2^{\frac{5}{3}}\newlineP(10)=5.4×cube root of 32P(10) = 5.4 \times \text{cube root of } 32\newlineP(10)5.4×3.1748P(10) \approx 5.4 \times 3.1748\newlineP(10)17.144P(10) \approx 17.144
  8. Round to nearest integer: Round to the nearest integer.\newlineThe company exported approximately 1717 million barrels of oil annually after 1010 years.

More problems from Exponential growth and decay: word problems