Charlotte opened a savings account and deposited $800.00 as principal. The account earns 8% interest, compounded annually. What is the balance after 10 years?Use the formula A=P(1+nr)nt, where A is the balance (final amount), P is the principal (starting amount), r is the interest rate expressed as a decimal, n is the number of times per year that the interest is compounded, and t is the time in years.Round your answer to the nearest cent.
Q. Charlotte opened a savings account and deposited $800.00 as principal. The account earns 8% interest, compounded annually. What is the balance after 10 years?Use the formula A=P(1+nr)nt, where A is the balance (final amount), P is the principal (starting amount), r is the interest rate expressed as a decimal, n is the number of times per year that the interest is compounded, and t is the time in years.Round your answer to the nearest cent.
Identify values: Identify the values of P, r, n, and t. Principal amount (P) = $800.00 Interest rate (r) = 8% annually Number of times interest is compounded per year (n) = 1 (since it's compounded annually) Time in years (t) = 10 years
Convert interest rate: Convert the annual interest rate from a percentage to a decimal.r=8%=1008=0.08
Substitute into formula: Substitute the values into the compound interest formulaA=P(1+nr)ntA=800(1+10.08)(1×10)
Simplify expression: Simplify the expression inside the parentheses.1+10.08=1+0.08=1.08
Calculate final amount: Calculate the final amount A using the simplified expression.A=800×(1.08)10
Perform exponentiation: Perform the exponentiation.(1.08)10≈2.158925
Multiply principal amount: Multiply the principal amount by the result of the exponentiation to find the final balance.A=800×2.158925≈1727.14
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