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The function 
f is defined by 
f(x)=x^(3)+4-4sin(x^(2)). Use a calculator to write the equation of the line tangent to the graph of 
f when 
x=2.5. You should round all decimals to 3 places.
Answer:

The function f f is defined by f(x)=x3+44sin(x2) f(x)=x^{3}+4-4 \sin \left(x^{2}\right) . Use a calculator to write the equation of the line tangent to the graph of f f when x=2.5 x=2.5 . You should round all decimals to 33 places.\newlineAnswer:

Full solution

Q. The function f f is defined by f(x)=x3+44sin(x2) f(x)=x^{3}+4-4 \sin \left(x^{2}\right) . Use a calculator to write the equation of the line tangent to the graph of f f when x=2.5 x=2.5 . You should round all decimals to 33 places.\newlineAnswer:
  1. Calculate Derivative of f: To find the equation of the tangent line to the graph of ff at x=2.5x = 2.5, we need to calculate the derivative of ff, which will give us the slope of the tangent line at that point. The derivative of ff with respect to xx is f(x)=3x28xsin(x2)cos(x2)f'(x) = 3x^2 - 8x\sin(x^2)\cos(x^2) (using the chain rule and product rule for differentiation).
  2. Evaluate Derivative at x=2.5x = 2.5: Now we need to evaluate the derivative at x=2.5x = 2.5 to find the slope of the tangent line at that point. So we calculate f(2.5)=3(2.5)28(2.5)sin((2.5)2)cos((2.5)2)f'(2.5) = 3(2.5)^2 - 8(2.5)\sin((2.5)^2)\cos((2.5)^2). Using a calculator, we find the value of f(2.5)f'(2.5) and round it to three decimal places.
  3. Calculate Slope of Tangent Line: After calculating, we find that f(2.5)3(2.5)28(2.5)sin((2.5)2)cos((2.5)2)18.7508(2.5)sin(6.25)cos(6.25)18.75020sin(6.25)cos(6.25)f'(2.5) \approx 3(2.5)^2 - 8(2.5)\sin((2.5)^2)\cos((2.5)^2) \approx 18.750 - 8(2.5)\sin(6.25)\cos(6.25) \approx 18.750 - 20\sin(6.25)\cos(6.25). We need to use a calculator to find the exact value of sin(6.25)\sin(6.25) and cos(6.25)\cos(6.25) and then multiply by 20-20 and add to 18.75018.750.
  4. Find y-coordinate at x=2.5x = 2.5: Using a calculator, we find that sin(6.25)0.003\sin(6.25) \approx -0.003 and cos(6.25)1.000\cos(6.25) \approx 1.000. Therefore, 20sin(6.25)cos(6.25)20(0.003)(1.000)0.060-20\sin(6.25)\cos(6.25) \approx -20(-0.003)(1.000) \approx 0.060. Adding this to 18.75018.750 gives us the slope of the tangent line: 18.750+0.06018.81018.750 + 0.060 \approx 18.810.
  5. Write Equation of Tangent Line: Next, we need to find the yy-coordinate of the point on the graph of ff where x=2.5x = 2.5. We do this by evaluating f(2.5)=(2.5)3+44sin((2.5)2)f(2.5) = (2.5)^3 + 4 - 4\sin((2.5)^2). Using a calculator, we find f(2.5)f(2.5) and round it to three decimal places.
  6. Simplify Equation to Slope-Intercept Form: After calculating, we find that f(2.5)(2.5)3+44sin(6.25)15.625+44(0.003)19.625+0.01219.637f(2.5) \approx (2.5)^3 + 4 - 4\sin(6.25) \approx 15.625 + 4 - 4(-0.003) \approx 19.625 + 0.012 \approx 19.637.
  7. Simplify Equation to Slope-Intercept Form: After calculating, we find that f(2.5)(2.5)3+44sin(6.25)15.625+44(0.003)19.625+0.01219.637f(2.5) \approx (2.5)^3 + 4 - 4\sin(6.25) \approx 15.625 + 4 - 4(-0.003) \approx 19.625 + 0.012 \approx 19.637.Now we have the slope of the tangent line, m=18.810m = 18.810, and a point on the tangent line, (2.5,19.637)(2.5, 19.637). We can use the point-slope form of a line, yy1=m(xx1)y - y_1 = m(x - x_1), to write the equation of the tangent line. Substituting the values, we get y19.637=18.810(x2.5)y - 19.637 = 18.810(x - 2.5).
  8. Simplify Equation to Slope-Intercept Form: After calculating, we find that f(2.5)(2.5)3+44sin(6.25)15.625+44(0.003)19.625+0.01219.637f(2.5) \approx (2.5)^3 + 4 - 4\sin(6.25) \approx 15.625 + 4 - 4(-0.003) \approx 19.625 + 0.012 \approx 19.637.Now we have the slope of the tangent line, m=18.810m = 18.810, and a point on the tangent line, (2.5,19.637)(2.5, 19.637). We can use the point-slope form of a line, yy1=m(xx1)y - y_1 = m(x - x_1), to write the equation of the tangent line. Substituting the values, we get y19.637=18.810(x2.5)y - 19.637 = 18.810(x - 2.5).Finally, we simplify the equation to get it into slope-intercept form, y=mx+by = mx + b. We distribute the slope and add 19.63719.637 to both sides to find the y-intercept, bb. y=18.810x18.810(2.5)+19.637y = 18.810x - 18.810(2.5) + 19.637.
  9. Simplify Equation to Slope-Intercept Form: After calculating, we find that f(2.5)(2.5)3+44sin(6.25)15.625+44(0.003)19.625+0.01219.637f(2.5) \approx (2.5)^3 + 4 - 4\sin(6.25) \approx 15.625 + 4 - 4(-0.003) \approx 19.625 + 0.012 \approx 19.637.Now we have the slope of the tangent line, m=18.810m = 18.810, and a point on the tangent line, (2.5,19.637)(2.5, 19.637). We can use the point-slope form of a line, yy1=m(xx1)y - y_1 = m(x - x_1), to write the equation of the tangent line. Substituting the values, we get y19.637=18.810(x2.5)y - 19.637 = 18.810(x - 2.5).Finally, we simplify the equation to get it into slope-intercept form, y=mx+by = mx + b. We distribute the slope and add 19.63719.637 to both sides to find the y-intercept, bb. y=18.810x18.810(2.5)+19.637y = 18.810x - 18.810(2.5) + 19.637.After simplifying, we find the equation of the tangent line to be y18.810x47.018+19.637y \approx 18.810x - 47.018 + 19.637, which simplifies to m=18.810m = 18.81000 (rounded to three decimal places).

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