The function f is defined by f(x)=x3+3−5sin(x2). Use a calculator to write the equation of the line tangent to the graph of f when x=1. You should round all decimals to 3 places.Answer:
Q. The function f is defined by f(x)=x3+3−5sin(x2). Use a calculator to write the equation of the line tangent to the graph of f when x=1. You should round all decimals to 3 places.Answer:
Calculate Derivative: To find the equation of the tangent line at x=1, we first need to calculate the derivative of the function f(x) to find the slope of the tangent line at that point.The derivative of f(x)=x3+3−5sin(x2) using the power rule and the chain rule is:f′(x)=3x2−10x⋅cos(x2).Now we need to evaluate this derivative at x=1.
Evaluate Derivative at x=1: Evaluating the derivative at x=1 gives us: f′(1)=3(1)2−10(1)⋅cos(12)=3−10cos(1). Using a calculator, we find that cos(1) is approximately 0.540 (rounded to three decimal places). So, f′(1)≈3−10⋅0.540=3−5.4=−2.4. The slope of the tangent line at x=1 is approximately −2.4.
Find y-coordinate at x=1: Next, we need to find the y-coordinate of the point on the graph of f(x) where x=1. This is done by evaluating the original function at x=1.f(1)=13+3−5sin(12)=1+3−5sin(1).Using a calculator, we find that sin(1) is approximately 0.841 (rounded to three decimal places).So, f(1)≈1+3−5×0.841=4−4.205=−0.205.The y-coordinate of the point on the graph at x=1 is approximately −0.205.
Use Point-Slope Form: Now we have the slope of the tangent line −2.4 and a point on the line (1,−0.205). We can use the point-slope form of the equation of a line to find the equation of the tangent line:y−y1=m(x−x1), where m is the slope and (x1,y1) is the point on the line.Plugging in our values, we get:y−(−0.205)=−2.4(x−1).
Simplify and Finalize Equation: Simplifying the equation, we get:y+0.205=−2.4x+2.4.Subtracting 0.205 from both sides to get y by itself, we have:y=−2.4x+2.4−0.205.Combining like terms, we get:y=−2.4x+2.195.This is the equation of the tangent line, rounded to three decimal places.
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