The function f is defined by f(x)=x3+1+2sin(2x). Use a calculator to write the equation of the line tangent to the graph of f when x=0.5. You should round all decimals to 3 places.Answer:
Q. The function f is defined by f(x)=x3+1+2sin(2x). Use a calculator to write the equation of the line tangent to the graph of f when x=0.5. You should round all decimals to 3 places.Answer:
Calculate Derivative of f: To find the equation of the tangent line to the graph of f at x=0.5, we need to calculate the derivative of f, which will give us the slope of the tangent line at that point. The derivative of f with respect to x is f′(x)=3x2+4cos(2x).
Evaluate Derivative at x=0.5: Now we need to evaluate the derivative at x=0.5 to find the slope of the tangent line at that point. So we calculate f′(0.5)=3(0.5)2+4cos(2⋅0.5).
Find y-coordinate at x=0.5: Using a calculator, we find that f′(0.5)=3(0.25)+4cos(1) which is approximately 0.75+4(0.540) after rounding to three decimal places. This gives us f′(0.5)≈0.75+2.160=2.910.
Determine Slope and Point: Next, we need to find the y-coordinate of the point on the graph of f at x=0.5. We do this by evaluating f(0.5)=(0.5)3+1+2sin(2⋅0.5).
Write Equation in Point-Slope Form: Using a calculator, we find that f(0.5)=0.125+1+2sin(1) which is approximately 0.125+1+2(0.841) after rounding to three decimal places. This gives us f(0.5)≈0.125+1+1.682=2.807.
Convert to Slope-Intercept Form: Now we have the slope of the tangent line, m=2.910, and a point on the tangent line, (0.5,2.807). We can use the point-slope form of a line to write the equation of the tangent line: y−y1=m(x−x1), where (x1,y1) is the point on the line.
Final Equation: Substituting the values we have, the equation of the tangent line is y−2.807=2.910(x−0.5).
Final Equation: Substituting the values we have, the equation of the tangent line is y−2.807=2.910(x−0.5).To write the equation in slope-intercept form, we distribute the slope on the right side and add 2.807 to both sides: y=2.910x−1.455+2.807.
Final Equation: Substituting the values we have, the equation of the tangent line is y−2.807=2.910(x−0.5).To write the equation in slope-intercept form, we distribute the slope on the right side and add 2.807 to both sides: y=2.910x−1.455+2.807.Simplifying the equation, we get y=2.910x+1.352 after rounding to three decimal places.
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