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The function 
f is defined by 
f(x)=x^(2)-sin(x). Use a calculator to write the equation of the line tangent to the graph of 
f when 
x=0.5. You should round all decimals to 3 places.
Answer:

The function f f is defined by f(x)=x2sin(x) f(x)=x^{2}-\sin (x) . Use a calculator to write the equation of the line tangent to the graph of f f when x=0.5 x=0.5 . You should round all decimals to 33 places.\newlineAnswer:

Full solution

Q. The function f f is defined by f(x)=x2sin(x) f(x)=x^{2}-\sin (x) . Use a calculator to write the equation of the line tangent to the graph of f f when x=0.5 x=0.5 . You should round all decimals to 33 places.\newlineAnswer:
  1. Calculate Derivative: To find the equation of the tangent line to the graph of f(x)f(x) at x=0.5x = 0.5, we need to calculate the derivative of f(x)f(x) to get the slope of the tangent line at that point.\newlineThe derivative of f(x)=x2sin(x)f(x) = x^2 - \sin(x) is f(x)=2xcos(x)f'(x) = 2x - \cos(x).
  2. Evaluate Derivative at x=0.5x=0.5: Now we need to evaluate the derivative at x=0.5x = 0.5 to find the slope of the tangent line.f(0.5)=2(0.5)cos(0.5).f'(0.5) = 2(0.5) - \cos(0.5).Using a calculator, we find that cos(0.5)\cos(0.5) is approximately 0.8770.877, rounded to three decimal places.So, f(0.5)10.877=0.123.\text{So, } f'(0.5) \approx 1 - 0.877 = 0.123.
  3. Find y-coordinate at x=0.5x=0.5: Next, we need to find the y-coordinate of the point on the graph of f(x)f(x) at x=0.5x = 0.5 to use it in the point-slope form of the equation of the tangent line.\newlinef(0.5)=(0.5)2sin(0.5)f(0.5) = (0.5)^2 - \sin(0.5).\newlineUsing a calculator, we find that sin(0.5)\sin(0.5) is approximately 0.4790.479, rounded to three decimal places.\newlineSo, f(0.5)0.250.479=0.229f(0.5) \approx 0.25 - 0.479 = -0.229.
  4. Use Point-Slope Form: With the slope of the tangent line and the point (0.5,0.229)(0.5, -0.229), we can use the point-slope form of the equation of a line: yy1=m(xx1)y - y_1 = m(x - x_1), where mm is the slope and (x1,y1)(x_1, y_1) is the point on the line.\newlinePlugging in our values, we get: y(0.229)=0.123(x0.5)y - (-0.229) = 0.123(x - 0.5).
  5. Simplify Equation: Simplify the equation to get it into the slope-intercept form y=mx+by = mx + b.y+0.229=0.123x0.0615y + 0.229 = 0.123x - 0.0615. Now, we add 0.06150.0615 to both sides to isolate yy.y=0.123x0.0615+0.229y = 0.123x - 0.0615 + 0.229.
  6. Combine Constants: Finally, we combine the constants to get the final equation of the tangent line.\newliney=0.123x+0.1675y = 0.123x + 0.1675.\newlineThis is the equation of the tangent line to the graph of f(x)f(x) at x=0.5x = 0.5, rounded to three decimal places.

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