The function f is defined by f(x)=x2+5+3sin(2x). Use a calculator to write the equation of the line tangent to the graph of f when x=1. You should round all decimals to 3 places.Answer:
Q. The function f is defined by f(x)=x2+5+3sin(2x). Use a calculator to write the equation of the line tangent to the graph of f when x=1. You should round all decimals to 3 places.Answer:
Calculate Derivative: To find the equation of the tangent line at x=1, we first need to calculate the derivative of the function f(x) to find the slope of the tangent line at that point.The derivative of f(x)=x2+5+3sin(2x) is f′(x)=2x+3×2cos(2x)=2x+6cos(2x).Now we need to evaluate this derivative at x=1.
Evaluate Derivative at x=1: Evaluating the derivative at x=1 gives us f′(1)=2(1)+6cos(2(1))=2+6cos(2). Using a calculator, we find that cos(2) is approximately 0.540. So, f′(1)≈2+6×0.540=2+3.24=5.24. We round this to three decimal places, so the slope of the tangent line at x=1 is approximately 5.240.
Find y-coordinate at x=1: Next, we need to find the y-coordinate of the point on the graph of f(x) where x=1. We do this by evaluating the original function at x=1: f(1)=12+5+3sin(2⋅1)=1+5+3sin(2). Using a calculator, we find that sin(2) is approximately 0.909. So, f(1)≈1+5+3⋅0.909=6+2.727=8.727. We round this to three decimal places, so the y-coordinate is approximately 8.727.
Write Point-Slope Equation: Now we have the slope of the tangent line m=5.240 and a point on the tangent line x=1,y≈8.727. We can use the point-slope form of a line to write the equation of the tangent line: y−y1=m(x−x1). Substituting the known values, we get y−8.727=5.240(x−1).
Convert to Slope-Intercept Form: To write the equation in slope-intercept formy=mx+b, we simplify the equation from the previous step:y=5.240(x−1)+8.727y=5.240x−5.240+8.727y=5.240x+3.487We round the y-intercept to three decimal places, so the equation of the tangent line is y≈5.240x+3.487.
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