Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

The equation of line 
u is 
2x+9y=5. Line 
v is parallel to line 
u and passes through 
(-9,-5). What is the equation of line 
v ?

The equation of line u u is 2x+9y=5 2 x+9 y=5 . Line v v is parallel to line u u and passes through (9,5) (-9,-5) . What is the equation of line v v ?

Full solution

Q. The equation of line u u is 2x+9y=5 2 x+9 y=5 . Line v v is parallel to line u u and passes through (9,5) (-9,-5) . What is the equation of line v v ?
  1. Find Slope of Line uu: Determine the slope of line uu. Line uu has the equation 2x+9y=52x + 9y = 5. To find the slope, we need to rewrite this equation in slope-intercept form, which is y=mx+by = mx + b, where mm is the slope.
  2. Convert to Slope-Intercept Form: Convert the equation of line uu into slope-intercept form. Starting with 2x+9y=52x + 9y = 5, we subtract 2x2x from both sides to get 9y=2x+59y = -2x + 5. Then, we divide both sides by 99 to isolate yy, which gives us y=(2/9)x+5/9y = (-2/9)x + 5/9. The slope of line uu is 2/9-2/9.
  3. Parallel Line vv Slope: Since line vv is parallel to line uu, it will have the same slope.\newlineThe slope of line vv is also 29-\frac{2}{9}.
  4. Use Point-Slope Form: Use the point-slope form to find the equation of line vv. The point-slope form of a line is yy1=m(xx1)y - y_1 = m(x - x_1), where mm is the slope and (x1,y1)(x_1, y_1) is a point on the line. We know that line vv passes through the point (9,5)(-9, -5) and has a slope of 29-\frac{2}{9}.
  5. Plug Slope and Point: Plug the slope and the point into the point-slope form equation.\newlineUsing the point (9,5)(-9, -5) and the slope 29-\frac{2}{9}, we get y(5)=(29)(x(9))y - (-5) = \left(-\frac{2}{9}\right)(x - (-9)).
  6. Simplify Point-Slope Equation: Simplify the equation from the previous step.\newlineThis simplifies to y+5=(29)(x+9)y + 5 = \left(-\frac{2}{9}\right)(x + 9).
  7. Distribute Slope: Distribute the slope on the right side of the equation.\newlineThis gives us y+5=(29)x(29)(9)y + 5 = \left(-\frac{2}{9}\right)x - \left(\frac{2}{9}\right)(9).
  8. Simplify Constant Term: Simplify the constant term on the right side of the equation. Multiplying 29-\frac{2}{9} by 99 gives us 2-2. So the equation becomes y+5=(29)x2y + 5 = \left(-\frac{2}{9}\right)x - 2.
  9. Solve for y: Subtract 55 from both sides to solve for yy and put the equation in slope-intercept form.\newlineThis gives us y=(2/9)x25y = (-2/9)x - 2 - 5, which simplifies to y=(2/9)x7y = (-2/9)x - 7.

More problems from Write an equation for a parallel or perpendicular line