The equation of line t is y=47x+2. Perpendicular to line t is line u, which passes through the point (2,−2). What is the equation of line u? Write the equation in slope-intercept form. Write the numbers in the equation as simplified proper fractions, improper fractions, or integers.
Q. The equation of line t is y=47x+2. Perpendicular to line t is line u, which passes through the point (2,−2). What is the equation of line u? Write the equation in slope-intercept form. Write the numbers in the equation as simplified proper fractions, improper fractions, or integers.
Determine slope of line t: Determine the slope of line t.The equation of line t is given as y=47x+2. The slope (m) of a line in the slope-intercept form y=mx+b is the coefficient of x. Therefore, the slope of line t is 47.
Find slope of line u: Find the slope of line u. Since line u is perpendicular to line t, its slope will be the negative reciprocal of the slope of line t. The negative reciprocal of 47 is −74. Therefore, the slope of line u is −74.
Use point-slope form: Use the point-slope form to find the equation of line u. We have the slope of line u−74 and a point through which it passes (2,−2). The point-slope form of a line's equation is y−y1=m(x−x1), where m is the slope and (x1,y1) is the point on the line. Plugging in the values, we get y−(−2)=−74(x−2).
Simplify to slope-intercept form: Simplify the equation to slope-intercept form.Starting with y+2=−74(x−2), distribute the slope −74 across (x−2) to get y+2=−74x+78. Then, subtract 2 from both sides to isolate y, which gives us y=−74x+78−714. Simplifying the y-intercept, we get y=−74x−76.
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