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The equation of line ss is y=35x+25y = \frac{3}{5}x + \frac{2}{5}. Line tt, which is parallel to line ss, includes the point (2,1)(2,1). What is the equation of line tt?\newlineWrite the equation in slope-intercept form. Write the numbers in the equation as simplified proper fractions, improper fractions, or integers.

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Q. The equation of line ss is y=35x+25y = \frac{3}{5}x + \frac{2}{5}. Line tt, which is parallel to line ss, includes the point (2,1)(2,1). What is the equation of line tt?\newlineWrite the equation in slope-intercept form. Write the numbers in the equation as simplified proper fractions, improper fractions, or integers.
  1. Check Slope Match: Line tt is parallel to line ss. Do their slopes match? Yes, parallel lines have the same slope.
  2. Find Slope of Line s: Equation of line s: \newliney=35x+25y = \frac{3}{5}x + \frac{2}{5}\newlineFind the slope of line s.\newlineCompare y=35x+25y = \frac{3}{5}x + \frac{2}{5} with y=mx+by = mx + b.\newlinem=35m = \frac{3}{5}\newlineSlope of line s: 35\frac{3}{5}
  3. Find Slope of Line tt: Line tt is parallel to ss.\newlineSlope of line ss: 35\frac{3}{5}\newlineFind the slope of line tt.\newlineSince line tt is parallel to line ss, its slope is also 35\frac{3}{5}.\newlineSlope of line tt: 35\frac{3}{5}
  4. Find y-intercept of Line t: For line t: \newlineSlope (m): 35\frac{3}{5} \newlinePoint: (2,1)(2, 1) \newlinePlug these values in y=mx+by = mx + b and find the y-intercept.\newline1=35(2)+b1 = \frac{3}{5}(2) + b \newline1=65+b1 = \frac{6}{5} + b\newlineSubtract 65\frac{6}{5} from both sides to solve for bb.\newline1−65=b1 - \frac{6}{5} = b\newline55−65=b\frac{5}{5} - \frac{6}{5} = b\newline−15=b-\frac{1}{5} = b
  5. Equation of Line t: For line t: \newlineSlope mm: 35\frac{3}{5} \newliney-intercept bb: −15-\frac{1}{5} \newlineWhat is the equation of the line t in slope-intercept form?\newlineSubstitute 35\frac{3}{5} for mm and −15-\frac{1}{5} for bb in y=mx+by = mx + b. \newliney=35x−15y = \frac{3}{5}x - \frac{1}{5}

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