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The equation of line qq is y=3x2y = 3x - 2. Line rr is perpendicular to line qq and passes through (1,3)(1,3). What is the equation of line rr?\newlineWrite the equation in slope-intercept form.

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Q. The equation of line qq is y=3x2y = 3x - 2. Line rr is perpendicular to line qq and passes through (1,3)(1,3). What is the equation of line rr?\newlineWrite the equation in slope-intercept form.
  1. Perpendicular Lines Slopes: Line rr is perpendicular to line qq. Are their slopes the same or opposite reciprocals? Slopes of perpendicular lines are opposite reciprocals.
  2. Equation of Line q: Equation of line q: \newliney=3x2y = 3x - 2\newlineFind the slope of line q.\newlineCompare y=3x2y = 3x - 2 with y=mx+by = mx + b.\newlinem=3m = 3\newlineSlope of line q: 33
  3. Slope of Line rr: Line rr is perpendicular to qq.\newlineSlope of line qq: 33\newlineFind the slope of line rr.\newlineOpposite reciprocal of 33 is 13-\frac{1}{3}.\newlineSlope of line rr: 13-\frac{1}{3}
  4. Y-Intercept Calculation: For line rr: \newlineSlope (mm): 13-\frac{1}{3} \newlinePoint: (1,3)(1, 3) \newlinePlug these values in y=mx+by = mx + b and find the y-intercept.\newline3=13(1)+b3 = -\frac{1}{3}(1) + b \newline3=13+b3 = -\frac{1}{3} + b\newline3+13=b3 + \frac{1}{3} = b\newline103=b\frac{10}{3} = b
  5. Equation of Line r: For line r: \newlineSlope mm: 13-\frac{1}{3} \newliney-intercept bb: 103\frac{10}{3} \newlineWhat is the equation of the line r in slope-intercept form?\newlineSubstitute 13-\frac{1}{3} for mm and 103\frac{10}{3} for bb in y=mx+by = mx + b. \newliney=13x+103y = -\frac{1}{3}x + \frac{10}{3}

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