The equation of line p is y+5= -10(x+2). Line q is perpendicular to line p and passes through (-1,-1). What is the equation of line q ? Write the equation in slope-intercept form. Write the numbers in the equation as simplified proper fractions, improper fractions, or integers.

Question

The equation of line  p is  y+5=  -10(x+2). Line  q is perpendicular to line  p and passes through  (-1,-1). What is the equation of line  q ? Write the equation in slope-intercept form. Write the numbers in the equation as simplified proper fractions, improper fractions, or integers.

Bytelearn · Accepted Answer

Find Slope of Line p: First, we need to find the slope of line p by putting its equation into slope-intercept form (y = mx + b). y + 5 = -10(x + 2) y = -10x - 20 - 5 y = -10x - 25 The slope (m) of line p is -10.Determine Slope of Line q: Since line q is perpendicular to line p, its slope will be the opposite reciprocal of the slope of line p. The opposite reciprocal of -10 is 1/10. So, the slope (m) of line q is 1/10.Use Point-Slope Form: Now we have the slope of line q and a point (-1, -1) through which it passes. We can use the point-slope form to find the equation of line q. The point-slope form is y - y1 = m(x - x1), where m is the slope and (x1, y1) is the point.Plug in Values: Plugging the slope and the point into the point-slope form, we get: y - (-1) = 1/10(x - (-1)) y + 1 = 1/10(x + 1)Convert to Slope-Intercept Form: Now we need to solve for y to put the equation in slope-intercept form. y = 1/10x + 1/10 - 1 y = 1/10x + 1/10 - 10/10 y = 1/10x - 9/10

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