The equation of line k is y-2=(1)/(2)(x-6). Perpendicular to line k is line ℓ, which passes through the point (-1,-6). What is the equation of line nn

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The equation of line  k is  y-2=(1)/(2)(x-6). Perpendicular to line  k is line  ℓ, which passes through the point  (-1,-6). What is the equation of line  nn

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Determine slope of line k: Determine the slope of line k. The equation of line k is given in point-slope form: y - 2 = 1/2(x - 6). The slope of line k is the coefficient of (x - 6), which is 1/2.Find slope of line ℓ: Find the slope of line ℓ, which is perpendicular to line k. Since line ℓ is perpendicular to line k, its slope will be the negative reciprocal of the slope of line k. The negative reciprocal of 1/2 is -2. Therefore, the slope of line ℓ is -2.Use point-slope form: Use the point-slope form to write the equation of line ℓ. Line ℓ passes through the point (-1, -6) and has a slope of -2. The point-slope form of a line is y - y1 = m(x - x1), where m is the slope and (x1, y1) is a point on the line. Plugging in the slope and the point into the point-slope form, we get y - (-6) = -2(x - (-1)).Simplify equation of line ℓ: Simplify the equation of line ℓ. Simplify the equation from the previous step: y + 6 = -2(x + 1). Distribute the -2: y + 6 = -2x - 2. Subtract 6 from both sides to get the equation in slope-intercept form: y = -2x - 8.

The equation of line $k$ is $y-2=\frac{1}{2}(x-6)$ . Perpendicular to line $k$ is line $\ell$ , which passes through the point $(-1,-6)$ . What is the equation of line $l$ ?

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The equation of line k k k is y−2=12(x−6) y-2=\frac{1}{2}(x-6) y−2=21​(x−6). Perpendicular to line k k k is line ℓ \ell ℓ, which passes through the point (−1,−6) (-1,-6) (−1,−6). What is the equation of line lll?

The equation of line $k$ is $y-2=\frac{1}{2}(x-6)$ . Perpendicular to line $k$ is line $\ell$ , which passes through the point $(-1,-6)$ . What is the equation of line $l$ ?