The equation of line c is y=−7x+10. Line d is perpendicular to line c and passes through (7,4). What is the equation of line d?Write the equation in slope-intercept form.
Q. The equation of line c is y=−7x+10. Line d is perpendicular to line c and passes through (7,4). What is the equation of line d?Write the equation in slope-intercept form.
Determine slope of line c: Determine the slope of line c. The equation of line c is given as y=−7x+10. The slope (m) of a line in the slope-intercept form y=mx+b is the coefficient of x. Therefore, the slope of line c is −7.
Find slope of line d: Find the slope of line d. Since line d is perpendicular to line c, its slope will be the negative reciprocal of the slope of line c. The negative reciprocal of −7 is 71. Therefore, the slope of line d is 71.
Use point-slope form: Use the point-slope form to find the equation of line d. We have the slope of line d (71) and a point through which it passes (7,4). The point-slope form of a line is (y−y1)=m(x−x1), where m is the slope and (x1,y1) is the point on the line. Plugging in the values, we get (y−4)=71(x−7).
Simplify to slope-intercept form: Simplify the equation to slope-intercept form.To get the slope-intercept form y=mx+b, we distribute the slope on the right side of the equation and then isolate y:y−4=71×x−71×7y−4=71×x−1y=71×x−1+4y=71×x+3
Verify the equation: Verify the equation.The equation y=71×x+3 is in slope-intercept form, with a slope of 71 and a y-intercept of 3. This line is perpendicular to line c, which has a slope of −7, and passes through the point (7,4), as required.
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