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The equation for line uu can be written as y=94x+1y = -\frac{9}{4}x + 1. Line vv, which is perpendicular to line uu, includes the point (3,2)(-3,2). What is the equation of line vv?\newlineWrite the equation in slope-intercept form. Write the numbers in the equation as simplified proper fractions, improper fractions, or integers.

Full solution

Q. The equation for line uu can be written as y=94x+1y = -\frac{9}{4}x + 1. Line vv, which is perpendicular to line uu, includes the point (3,2)(-3,2). What is the equation of line vv?\newlineWrite the equation in slope-intercept form. Write the numbers in the equation as simplified proper fractions, improper fractions, or integers.
  1. Determine slope of line uu: Determine the slope of line uu. The equation of line uu is given as y=94x+1y = -\frac{9}{4}x + 1. The slope (mm) of a line in the slope-intercept form y=mx+by = mx + b is the coefficient of xx. Therefore, the slope of line uu is 94-\frac{9}{4}.
  2. Find slope of line vv: Find the slope of line vv. Since line vv is perpendicular to line uu, its slope will be the negative reciprocal of the slope of line uu. The negative reciprocal of 94-\frac{9}{4} is 49\frac{4}{9}. Therefore, the slope of line vv is 49\frac{4}{9}.
  3. Use point-slope form: Use the point-slope form to find the equation of line vv. We have the slope of line vv (49\frac{4}{9}) and a point through which it passes (3,2-3,2). The point-slope form of a line is (yy1)=m(xx1)(y - y_1) = m(x - x_1), where mm is the slope and (x1,y1)(x_1, y_1) is the point on the line. Plugging in the values, we get (y2)=49(x(3))(y - 2) = \frac{4}{9}(x - (-3)).
  4. Simplify equation of line v: Simplify the equation of line v.\newlineStarting with (y2)=49(x+3)(y - 2) = \frac{4}{9}(x + 3), we distribute the slope on the right side:\newliney2=49×x+49×3y - 2 = \frac{4}{9} \times x + \frac{4}{9} \times 3\newliney2=49×x+43y - 2 = \frac{4}{9} \times x + \frac{4}{3}\newlineNow, we add 22 to both sides to solve for yy:\newliney=49×x+43+2y = \frac{4}{9} \times x + \frac{4}{3} + 2
  5. Convert constant term: Convert the constant term to a common denominator and combine terms.\newlineThe common denominator for 43\frac{4}{3} and 22 is 33. So we convert 22 to 63\frac{6}{3}:\newliney=49×x+43+63y = \frac{4}{9} \times x + \frac{4}{3} + \frac{6}{3}\newliney=49×x+(4+63)y = \frac{4}{9} \times x + \left(\frac{4 + 6}{3}\right)\newliney=49×x+103y = \frac{4}{9} \times x + \frac{10}{3}\newlineThis is the equation of line vv in slope-intercept form.

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