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The equation for line tt can be written as y=4x8y = 4x - 8. Line uu, which is perpendicular to line tt, includes the point (8,8)(8,8). What is the equation of line uu? \newlineWrite the equation in slope-intercept form.

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Q. The equation for line tt can be written as y=4x8y = 4x - 8. Line uu, which is perpendicular to line tt, includes the point (8,8)(8,8). What is the equation of line uu? \newlineWrite the equation in slope-intercept form.
  1. Determine slope of line t: Determine the slope of line t.\newlineThe equation of line t is given as y=4x8y = 4x - 8. The slope-intercept form of a line is y=mx+by = mx + b, where mm is the slope and bb is the y-intercept. Comparing the given equation with the slope-intercept form, we find that the slope (mm) of line t is 44.
  2. Find slope of line uu: Find the slope of line uu. Since line uu is perpendicular to line tt, its slope will be the negative reciprocal of the slope of line tt. The negative reciprocal of 44 is 14-\frac{1}{4}. Therefore, the slope of line uu is 14-\frac{1}{4}.
  3. Use point-slope form: Use the point-slope form to find the equation of line uu. We have the slope of line uu 14-\frac{1}{4} and a point through which it passes (8,8)(8,8). The point-slope form of a line is yy1=m(xx1)y - y_1 = m(x - x_1), where mm is the slope and (x1,y1)(x_1, y_1) is the point on the line. Plugging in the values, we get y8=14(x8)y - 8 = -\frac{1}{4}(x - 8).
  4. Simplify to slope-intercept form: Simplify the equation to slope-intercept form. Starting with y8=14(x8)y - 8 = -\frac{1}{4}(x - 8), we distribute the slope on the right side to get y8=14x+2y - 8 = -\frac{1}{4}x + 2. Then, we add 88 to both sides to solve for yy, resulting in y=14x+2+8y = -\frac{1}{4}x + 2 + 8. Simplifying further, we get y=14x+10y = -\frac{1}{4}x + 10.

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