The equation for line s can be written as y= – 10x+ 5/4 . Parallel to line s is line t, which passes through the point ( – 1,3). What is the equation of line t?

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The equation for line s can be written as y= – 10x+  5/4 . Parallel to line s is line t, which passes through the point ( – 1,3). What is the equation of line t?

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Find Slope of Line s: Determine the slope of line s. Line s has the equation y = –10x + 5/4. The slope of a line in the slope-intercept form y = mx + b is the coefficient of x, which is m. The slope of line s is –10.Determine Parallel Line Slope: Since line t is parallel to line s, it must have the same slope. Parallel lines have identical slopes. Therefore, the slope of line t is also –10.Use Point-Slope Form: Use the point-slope form to find the equation of line t. The point-slope form of a line is y - y1 = m(x - x1), where m is the slope and (x1, y1) is a point on the line. We know the slope (m) is –10 and the point (x1, y1) is (–1, 3).Plug in Slope and Point: Plug the slope and point into the point-slope form to get the equation of line t. y - 3 = –10(x - (–1)) y - 3 = –10(x + 1)Distribute and Simplify: Distribute the slope on the right side of the equation and simplify. y - 3 = –10x - 10Solve for y: Solve for y to put the equation in slope-intercept form. y = –10x - 10 + 3 y = –10x - 7

The equation for line $s$ can be written as $y= -10x+ \frac{5}{4}$ . Parallel to line $s$ is line $t$ , which passes through the point $(-1,3)$ . What is the equation of line $t$ ?

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The equation for line $s$ can be written as $y= -10x+ \frac{5}{4}$ . Parallel to line $s$ is line $t$ , which passes through the point $(-1,3)$ . What is the equation of line $t$ ?