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The equation for line jj can be written as y=18x+7y = \frac{1}{8}x + 7. Parallel to line jj is line kk, which passes through the point (−3,−1)(-3,-1). What is the equation of line kk?\newlineWrite the equation in slope-intercept form. Write the numbers in the equation as simplified proper fractions, improper fractions, or integers.

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Q. The equation for line jj can be written as y=18x+7y = \frac{1}{8}x + 7. Parallel to line jj is line kk, which passes through the point (−3,−1)(-3,-1). What is the equation of line kk?\newlineWrite the equation in slope-intercept form. Write the numbers in the equation as simplified proper fractions, improper fractions, or integers.
  1. Slope Match: Line kk is parallel to line jj. Do their slopes match? Yes, parallel lines have the same slope.
  2. Equation of Line j: Equation of line j: \newliney=18x+7y = \frac{1}{8}x + 7\newlineFind the slope of line j.\newlineCompare y=18x+7y = \frac{1}{8}x + 7 with y=mx+by = mx + b.\newlinem=18m = \frac{1}{8}\newlineSlope of line j: 18\frac{1}{8}
  3. Slope of Line kk: Line kk is parallel to jj.\newlineSlope of line jj: 18\frac{1}{8}\newlineFind the slope of line kk.\newlineSince line kk is parallel to line jj, its slope is also 18\frac{1}{8}.\newlineSlope of line kk: 18\frac{1}{8}
  4. Y-Intercept of Line k: For line k: \newlineSlope mm: 18\frac{1}{8} \newlinePoint: (−3,−1)(-3, -1) \newlinePlug these values in y=mx+by = mx + b and find the y-intercept.\newline−1=18(−3)+b-1 = \frac{1}{8}(-3) + b \newline−1=−38+b-1 = -\frac{3}{8} + b\newlineAdd 38\frac{3}{8} to both sides to solve for b.\newline−1+38=b-1 + \frac{3}{8} = b\newline−88+38=b-\frac{8}{8} + \frac{3}{8} = b\newline−58=b-\frac{5}{8} = b
  5. Equation of Line k: For line k: \newlineSlope mm: 18\frac{1}{8} \newliney-intercept bb: −58\frac{-5}{8} \newlineWhat is the equation of the line k in slope-intercept form?\newlineSubstitute 18\frac{1}{8} for mm and −58\frac{-5}{8} for bb in y=mx+by = mx + b. \newliney=18x−58y = \frac{1}{8}x - \frac{5}{8}

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