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The energy usages per day (in kilowatt-hours) of houses on Hamlet Avenue are listed below.

30,23,38,36,33
Find the mean energy usage per day.

kWh

The energy usages per day (in kilowatt-hours) of houses on Hamlet Avenue are listed below.\newline30,23,38,36,33 30,23,38,36,33 \newlineFind the mean energy usage per day.\newlinekWh \mathrm{kWh}

Full solution

Q. The energy usages per day (in kilowatt-hours) of houses on Hamlet Avenue are listed below.\newline30,23,38,36,33 30,23,38,36,33 \newlineFind the mean energy usage per day.\newlinekWh \mathrm{kWh}
  1. Calculate Total Energy Usage: To find the mean energy usage per day, we need to sum up all the individual energy usages and then divide by the number of houses.\newlineCalculation: Sum of energy usages = 30+23+38+36+3330 + 23 + 38 + 36 + 33
  2. Find Number of Houses: Perform the addition to find the total energy usage.\newlineCalculation: Total energy usage = 30+23+38+36+33=16030 + 23 + 38 + 36 + 33 = 160 kWh
  3. Calculate Mean Energy Usage: Count the number of houses to find the divisor for calculating the mean.\newlineCalculation: Number of houses =5= 5
  4. Calculate Mean Energy Usage: Count the number of houses to find the divisor for calculating the mean.\newlineCalculation: Number of houses =5= 5Divide the total energy usage by the number of houses to find the mean energy usage per day.\newlineCalculation: Mean energy usage per day =Total energy usageNumber of houses=160kWh5= \frac{\text{Total energy usage}}{\text{Number of houses}} = \frac{160 \text{kWh}}{5}
  5. Calculate Mean Energy Usage: Count the number of houses to find the divisor for calculating the mean.\newlineCalculation: Number of houses = 55Divide the total energy usage by the number of houses to find the mean energy usage per day.\newlineCalculation: Mean energy usage per day = Total energy usage / Number of houses = 160kWh/5160 \, \text{kWh} / 5Perform the division to find the mean energy usage per day.\newlineCalculation: Mean energy usage per day = 160kWh/5=32kWh160 \, \text{kWh} / 5 = 32 \, \text{kWh}

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