The country of Freedonia has decided to reduce its carbondioxide emission by 35% each year. This year the country emitted 40 million tons of carbon-dioxide.Write a function that gives Freedonia's carbon-dioxide emissions in million tons, E(t),t years from today.E(t)=□
Q. The country of Freedonia has decided to reduce its carbondioxide emission by 35% each year. This year the country emitted 40 million tons of carbon-dioxide.Write a function that gives Freedonia's carbon-dioxide emissions in million tons, E(t),t years from today.E(t)=□
Understand Exponential Decay: To create a function that models the carbon-dioxide emissions in Freedonia t years from today, we need to understand that a reduction of 35% each year means that each year, Freedonia will emit only 65% (100%−35%) of the carbon-dioxide it emitted the previous year. This is an example of exponential decay, and the general formula for exponential decay is:E(t)=E0×(1−r)twhere:E(t) is the amount after t years,E0 is the initial amount (the amount today),r is the decay rate (as a decimal), andt is the time in years.Given that the initial amount of carbon-dioxide is 35%0 million tons and the decay rate is 35%, or 35%2 as a decimal, we can substitute these values into the formula.
Convert Percentage to Decimal: First, we convert the percentage reduction to a decimal by dividing by 100. So, 35% becomes 0.35.Next, we subtract this decimal from 1 to find the percentage that remains each year. This gives us 1−0.35=0.65.Now we can write the function for E(t) using the initial amount of carbon-dioxide, which is 40 million tons, and the decay factor, which is 0.65.E(t)=40×(0.65)t
Write Emission Function: The function E(t)=40×(0.65)t now represents the carbon-dioxide emissions in million tons, t years from today. This function can be used to calculate the emissions for any given year t by substituting the value of t into the function.To check for any mathematical errors, let's consider the case when t=0, which should give us the initial value of 40 million tons.E(0)=40×(0.65)0=40×1=40Since any number to the power of 0 is 1, and 40 times 1 is 40, the function checks out for t=0.
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