the area of al rectangular plate is 40/7 m^2 and its length is 15/4 m . find its breadth and perimeter

Calculate Breadth: To find the breadth, we need to divide the area by the length. Area = Length * Breadth So, Breadth = Area / Length We are given that the Area = 40/7 m^2 and the Length = 15/4 m. Now we calculate the breadth. Breadth = (40/7) / (15/4) Breadth = (40/7) * (4/15) Breadth = 160/105 Breadth = 32/21Find Perimeter: Now that we have the breadth, we can find the perimeter of the rectangle. Perimeter = 2 * (Length + Breadth) We know that Length = 15/4 m and Breadth = 32/21 m. Now we calculate the perimeter. Perimeter = 2 * ((15/4) + (32/21)) To add these two fractions, we need a common denominator, which would be 4*21 = 84. Perimeter = 2 * ((15*21/84) + (32*4/84)) Perimeter = 2 * ((315/84) + (128/84)) Perimeter = 2 * (443/84) Perimeter = 886/84 Perimeter = 443/42

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the area of al rectangular plate is $\frac{40}{7}\,\text{m}^2$ and its length is $\frac{15}{4}\,\text{m}$ . find its breadth and perimeter

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Q. the area of al rectangular plate is

\frac{40}{7}\,\text{m}^2

and its length is

\frac{15}{4}\,\text{m}

. find its breadth and perimeter

Calculate Breadth: To find the breadth, we need to divide the area by the length. $\newline$ $\text{Area} = \text{Length} \times \text{Breadth}$ $\newline$ So, $\text{Breadth} = \frac{\text{Area}}{\text{Length}}$ $\newline$ We are given that the $\text{Area} = \frac{40}{7} \, \text{m}^2$ and the $\text{Length} = \frac{15}{4} \, \text{m}$ . $\newline$ Now we calculate the breadth. $\newline$ $\text{Breadth} = \frac{40}{7} / \frac{15}{4}$ $\newline$ $\text{Breadth} = \frac{40}{7} \times \frac{4}{15}$ $\newline$ $\text{Breadth} = \frac{160}{105}$ $\newline$ $\text{Breadth} = \frac{32}{21}$
Find Perimeter: Now that we have the breadth, we can find the perimeter of the rectangle. $\newline$ Perimeter = $2 \times (\text{Length} + \text{Breadth})$ $\newline$ We know that Length = $\frac{15}{4}$ m and Breadth = $\frac{32}{21}$ m. $\newline$ Now we calculate the perimeter. $\newline$ Perimeter = $2 \times (\left(\frac{15}{4}\right) + \left(\frac{32}{21}\right))$ $\newline$ To add these two fractions, we need a common denominator, which would be $4\times21 = 84$ . $\newline$ Perimeter = $2 \times (\left(\frac{15\times21}{84}\right) + \left(\frac{32\times4}{84}\right))$ $\newline$ Perimeter = $2 \times (\left(\frac{315}{84}\right) + \left(\frac{128}{84}\right))$ $\newline$ Perimeter = $2 \times \left(\frac{443}{84}\right)$ $\newline$ Perimeter = $\frac{886}{84}$ $\newline$ Perimeter = $\frac{443}{42}$