Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

The area of a parallelogram is 3 , and the lengths of its sides are 1.1 and 4.8 . Determine, to the nearest tenth of a degree, the measure of the obtuse angle of the parallelogram.
Answer:

The area of a parallelogram is 33 , and the lengths of its sides are 11.11 and 44.88 . Determine, to the nearest tenth of a degree, the measure of the obtuse angle of the parallelogram.\newlineAnswer:

Full solution

Q. The area of a parallelogram is 33 , and the lengths of its sides are 11.11 and 44.88 . Determine, to the nearest tenth of a degree, the measure of the obtuse angle of the parallelogram.\newlineAnswer:
  1. Identify Parallelogram Area Formula: To find the measure of the obtuse angle, we need to use the formula for the area of a parallelogram, which is A=base×heightA = \text{base} \times \text{height}. Here, we can consider the sides of lengths 1.11.1 and 4.84.8 as the base and the corresponding height, respectively. However, since we are looking for the obtuse angle, we need to find the height that corresponds to the side of length 4.84.8 as the base.
  2. Calculate Height Using Area Formula: The area of the parallelogram is given as 33. We can use the formula A=base×heightA = \text{base} \times \text{height}, where the base is 4.84.8. Let's denote the height as hh. So, we have 3=4.8×h3 = 4.8 \times h.
  3. Find Sine of Acute Angle: To find the height hh, we divide both sides of the equation by 4.84.8. So, h=34.8h = \frac{3}{4.8}.
  4. Calculate Acute Angle: Calculating the height hh gives us h=0.625h = 0.625.
  5. Find Obtuse Angle: Now that we have the height, we can find the sine of the acute angle θ\theta between the base and the height using the formula sin(θ)=oppositehypotenuse\sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}}. In this case, the opposite side is the height hh, and the hypotenuse is the side of length 1.11.1. So, sin(θ)=0.6251.1\sin(\theta) = \frac{0.625}{1.1}.
  6. Find Obtuse Angle: Now that we have the height, we can find the sine of the acute angle (θ\theta) between the base and the height using the formula sin(θ)=oppositehypotenuse\sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}}. In this case, the opposite side is the height hh, and the hypotenuse is the side of length 1.11.1. So, sin(θ)=0.6251.1\sin(\theta) = \frac{0.625}{1.1}.Calculating sin(θ)\sin(\theta) gives us sin(θ)0.56818\sin(\theta) \approx 0.56818.
  7. Find Obtuse Angle: Now that we have the height, we can find the sine of the acute angle θ\theta between the base and the height using the formula sin(θ)=oppositehypotenuse\sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}}. In this case, the opposite side is the height hh, and the hypotenuse is the side of length 1.11.1. So, sin(θ)=0.6251.1\sin(\theta) = \frac{0.625}{1.1}.Calculating sin(θ)\sin(\theta) gives us sin(θ)0.56818\sin(\theta) \approx 0.56818.To find the measure of the acute angle θ\theta, we take the inverse sine (arcsin) of 0.568180.56818. θ=arcsin(0.56818)\theta = \arcsin(0.56818).
  8. Find Obtuse Angle: Now that we have the height, we can find the sine of the acute angle θ\theta between the base and the height using the formula sin(θ)=oppositehypotenuse\sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}}. In this case, the opposite side is the height hh, and the hypotenuse is the side of length 1.11.1. So, sin(θ)=0.6251.1\sin(\theta) = \frac{0.625}{1.1}. Calculating sin(θ)\sin(\theta) gives us sin(θ)0.56818\sin(\theta) \approx 0.56818. To find the measure of the acute angle θ\theta, we take the inverse sine (arcsin) of 0.568180.56818. θ=arcsin(0.56818)\theta = \arcsin(0.56818). Calculating θ\theta gives us sin(θ)=oppositehypotenuse\sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}}11. Since this is the acute angle and we are looking for the obtuse angle, we subtract this from sin(θ)=oppositehypotenuse\sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}}22 to find the obtuse angle. The obtuse angle sin(θ)=oppositehypotenuse\sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}}33.
  9. Find Obtuse Angle: Now that we have the height, we can find the sine of the acute angle (θ\theta) between the base and the height using the formula sin(θ)=oppositehypotenuse\sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}}. In this case, the opposite side is the height hh, and the hypotenuse is the side of length 1.11.1. So, sin(θ)=0.6251.1\sin(\theta) = \frac{0.625}{1.1}.Calculating sin(θ)\sin(\theta) gives us sin(θ)0.56818\sin(\theta) \approx 0.56818.To find the measure of the acute angle θ\theta, we take the inverse sine (arcsin) of 0.568180.56818. θ=arcsin(0.56818)\theta = \arcsin(0.56818).Calculating θ\theta gives us sin(θ)=oppositehypotenuse\sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}}11. Since this is the acute angle and we are looking for the obtuse angle, we subtract this from sin(θ)=oppositehypotenuse\sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}}22 to find the obtuse angle. The obtuse angle sin(θ)=oppositehypotenuse\sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}}33.Calculating sin(θ)=oppositehypotenuse\sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}}44 gives us sin(θ)=oppositehypotenuse\sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}}55. This is the measure of the obtuse angle of the parallelogram, to the nearest tenth of a degree.

More problems from Find the magnitude of a three-dimensional vector