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Ten students sit together. Reatlife-Problem
(a) In how many ways can they sit if they sit in a row? 
10^(:):-3628800
(b) In how many ways can they sit if they sit in two rows with five seats each?
Hint 4

Ten students sit together. \newline(a) In how many ways can they sit if they sit in a row? \newline(b) In how many ways can they sit if they sit in two rows with five seats each?

Full solution

Q. Ten students sit together. \newline(a) In how many ways can they sit if they sit in a row? \newline(b) In how many ways can they sit if they sit in two rows with five seats each?
  1. Calculate Ways in a Row: Calculate the number of ways to arrange ten students in a row.\newlineUsing the formula for permutations, n!n!, where nn is the number of students:\newline10!=10×9×8×7×6×5×4×3×2×1=362880010! = 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 = 3628800
  2. Calculate Ways in Two Rows: Calculate the number of ways to arrange ten students in two rows of five each.\newlineFirst, choose 55 students for the first row (combination), then arrange them (permutation). Repeat for the second row.\newlineNumber of ways = ((105)×5!×5!)(10 \choose 5) \times 5! \times 5!\newline= (10!/(5!×5!))×5!×5!(10! / (5! \times 5!)) \times 5! \times 5!\newline= 10!/5!=3024010! / 5! = 30240

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