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sum_(n=0)^(1)(n+6)=

$\sum_{n=0}^{1}(n+6)=$

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Evaluate an exponential function

Full solution

Q.

\sum_{n=0}^{1}(n+6)=

Problem Understanding: Understand the problem. $\newline$ We need to calculate the sum of the expression $(n+6)$ for the values of $n$ from $0$ to $1$ .
Substituting $n=0$ : Substitute $n=0$ into the expression $(n+6)$ . When $n=0$ , the expression becomes $(0+6)$ which equals $6$ .
Substituting $n=1$ : Substitute $n=1$ into the expression $(n+6)$ . $\newline$ When $n=1$ , the expression becomes $(1+6)$ which equals $7$ .
Adding Results: Add the results from Step $2$ and Step $3$ . $\newline$ The sum is $6$ (from $n=0$ ) plus $7$ (from $n=1$ ), which equals $13$ .

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