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sum_(k=0)^(2)(2k+2)=

k=02(2k+2)= \sum_{k=0}^{2}(2 k+2)=

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Q. k=02(2k+2)= \sum_{k=0}^{2}(2 k+2)=
  1. Understanding the series: Understand the series and its terms.\newlineWe need to calculate the sum of the series where each term is given by the expression (2k+2)(2k+2) and kk ranges from 00 to 22.
  2. Calculating the first term: Calculate the first term of the series.\newlineSubstitute k=0k=0 into the expression (2k+2)(2k+2) to find the first term.\newlineFirst term: (2×0+2)=2(2\times 0+2) = 2
  3. Calculating the second term: Calculate the second term of the series.\newlineSubstitute k=1k=1 into the expression (2k+2)(2k+2) to find the second term.\newlineSecond term: (2×1+2)=4(2\times 1+2) = 4
  4. Calculating the third term: Calculate the third term of the series.\newlineSubstitute k=2k=2 into the expression (2k+2)(2k+2) to find the third term.\newlineThird term: (2×2+2)=6(2\times 2+2) = 6
  5. Summing all the terms: Sum all the terms of the series.\newlineAdd the first, second, and third terms together to get the total sum.\newlineTotal sum: 2+4+6=122 + 4 + 6 = 12

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